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3 years ago

What is the amplitude of this wave?

Physics

1 answer:

nikdorinn [45]3 years ago

5 0

Answer:

2.1 cm

Explanation:

The general equation for the graph is:

y = A cos(ωt + ∅)

A: amplitude, is the maximum and minimum value for y(t)

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Primary colors of light?

brilliants [131]

The primary colors of light are:

1. Green

2. Red

3.Blue

4. Yellow

5. White

6. Cyan

7. Magenta

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4 years ago

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A vector starts at the point (0.0) and ends at (3,-3). What is the angle of the displacement?

Naily [24]

Answer:

135degrees

Explanation:

Given that a vector starts at the point (0.0) and ends at (3,-3)

y component value = -3

x component value = 3

angle of the displacement theta = arctan(y/x)

theta = arctan(-3/3)

theta = arctan (-1)

theta = -45degrees

Since tan is negative in the second quadrant

theta = 180 - 45

theta = 135degrees

Hence the angle of the displacement is 135degrees

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3 years ago

A gyroscope flywheel of radius 3.21 cm is accelerated from rest at 13.2 rad/s2 until its angular speed is 2450 rev/min.

SIZIF [17.4K]

Answer:

Part a)

$a_t = 0.423 m/s^2$

Part b)

$a_c = 2113 m/s^2$

Part c)

$d = 80 m$

Explanation:

Part a)

as we know that angular acceleration of the wheel is given as

$\alpha = 13.2 rad/s^2$

now the radius of the wheel is given as

R = 3.21 cm

so the tangential acceleration is given as

$a_t = R\alpha$

$a_t = (0.0321)(13.2)$

$a_t = 0.423 m/s^2$

Part b)

frequency of the wheel at maximum speed is given as

$f = 2450 rev/min$

$f = \frac{2450}{60} = 40.8 rev/s$

now we know that

$\omega = 2\pi f = 2\pi(40.8) = 256.56 rad/s$

now radial acceleration is given as

$a_c = \omega^2 r$

$a_c = (256.56)^2(0.0321) = 2113 m/s^2$

Part c)

total angular displacement of the point on rim is given as

$\Delta \theta = \omega_0 t + \frac{1}{2}\alpha t^2$

here we know that

$\omega = \omega_0 + \alpha t$

$256.56 = 0 + 13.2 t$

$t = 19.4 s$

now angular displacement will be

$\Delta \theta = 0 + \frac{1}{2}(13.2)(19.4)^2$

$\Delta \theta = 2493.3 rad$

now the distance moved by the point on the rim is given as

$d = R\theta$

$d = (0.0321)(2493.3)$

$d = 80 m$

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3 years ago

You performed an experiment in which you measured the amount of water leaking through different types of roofs. For one roof, yo

Ostrovityanka [42]

Given:
m = 13.2 oz, the mass of water measured

Note that
$1 \, oz = (1 \, oz)*( \frac{1}{16} \, \frac{lb}{oz} )*( \frac{1}{2.2} \, \frac{kg}{lb} ) = 0.0284 \, kg$

Answer: 0.0284 kg

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3 years ago

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With no effort at all, you'll have deep and lasting relationships.<br> True<br> False

Firdavs [7]

The correct answer is false

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3 years ago