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never [62]
3 years ago
5

or points :-) 4000000000000000000000000000+88888888888888888888888888888888888888-11111111111111111111111111111111111=

Mathematics
1 answer:
Ivan3 years ago
6 0

Answer:

funny

Step-by-step explanation:

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What is equivalent to -23-(26)=x
ANTONII [103]
I’m not sure if this is what your looking for but x = -49
4 0
3 years ago
Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f
pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas  = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁)  = 0.999869

P(A/E₁) = 3%  = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}

=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}

\frac{0.2999607}{0.00000393+0.2999607}

\frac{0.2999607}{0.29996463}

= 0.999986898 ≈ 0.999987

6 0
3 years ago
Solve for k, 6k-2z=12
Alenkinab [10]
The previous question I answered was exactly like this.

6(4) - 2(6) = 12.

K = 4.
4 0
3 years ago
What is the average rate of change between (3,2) and (1,9)
hjlf

Answer:

-0.25

Step-by-step explanation:

1-3= -2

9-2= 8

-2/8= -0.25

7 0
3 years ago
Can someone answer this question please?
Mekhanik [1.2K]
Steps:
1. calculate the values of y at x=0,1,2. using y=5-x^2
2. calculate the areas of trapezoids (Bottom+Top)/2*height
3. add the areas.

1. 
x=0, y=5-0^2=5
x=1, y=5-1^2=4
x=2, y=5-2^2=1
2. 
Area of trapezoid 1 = (5+4)/2*1=4.5
Area of trapezoid 2 = (4+1)/2*1=2.5

Total area of both trapezoids = (4.5+2.5) = 7

Exact area by integration:
integral of (5-x^2)dx   from 0 to 2
=[5x-x^3/3] from 0 to 2
=[5(2-0)-(2^3-0^3)/3]
=10-8/3
=22/3
=7 1/3, slight greater than the estimation by trapezoids.

8 0
3 years ago
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