=40mn-12m+40mn-9mn+6n-24m+72mn-5mn-36mn
=102mn-36m+6n
<h3>
Answer: Choice A) 0.20</h3>
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Explanation:
Let's say there are 1000 students. The students must take math, science or they can take both simultaneously.
- 65% of them are in math. So there are 0.65*1000 = 650 math students.
- 43% are in science, leading to 0.43*1000 = 430 science students.
- 13% are in both so we have 0.13*1000 = 130 students who are in both.
Now onto the sentence that says "Suppose a high school student who is enrolled in a math class is selected at random"
This means we only focus on the 650 math students and ignore the 1000-650 = 350 students who aren't in math.
Of those 650 math students, 130 are also in science (since 130 are in both classes).
The probability we're after is therefore 130/650 = 0.20
Up, just put some points in the graphic and you'll see
So, that's

*Helpful To Know
![{5}^{ \frac{1}{2} } = \sqrt{5} \\ {5}^{ \frac{1}{3} } = \sqrt[3]{5} \\ {5}^{ \frac{1}{4} } = \sqrt[4]{5} \\ {5}^{ \frac{3}{2} } = \sqrt{ {5}^{3} } \: \: or \: {( \sqrt{5} )}^{3}](https://tex.z-dn.net/?f=%7B5%7D%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%20%3D%20%20%5Csqrt%7B5%7D%20%5C%5C%20%20%7B5%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B5%7D%20%20%5C%5C%20%7B5%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B5%7D%20%20%20%20%5C%5C%20%20%20%7B5%7D%5E%7B%20%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%3D%20%20%5Csqrt%7B%20%7B5%7D%5E%7B3%7D%20%7D%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%20%20%7B%28%20%5Csqrt%7B5%7D%20%29%7D%5E%7B3%7D%20)
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*Assuming that you want to covert to radicals
![( \sqrt{8} )( \sqrt{x} )( \sqrt[4]{ {y}^{3} } )](https://tex.z-dn.net/?f=%28%20%5Csqrt%7B8%7D%20%29%28%20%5Csqrt%7Bx%7D%20%29%28%20%5Csqrt%5B4%5D%7B%20%7By%7D%5E%7B3%7D%20%7D%20%29)
*Simplify