What is the range of the relation y = 3x2 + 4x if the domain is the set (-1,0, 1)?
1 answer:
Answer:
{ - 1, 0, 7 }
Step-by-step explanation:
Substitute the values of x from the domain into the relation to obtain the corresponding values of y , that is the range
x = - 1 : y = 3(- 1)² + 4(- 1) = 3(1) - 4 = 3 - 4 = - 1
x = 0 ; y = 3(0)² + 4(0) = 0 + 0 = 0
x = 1 : y = 3(1)² + 4(1) = 3 + 4 = 7
range is { - 1, 0, 7 }
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