Question

What is the range of the relation y = 3x2 + 4x if the domain is the set (-1,0, 1)?

Answer 1

Answer:

{ - 1, 0, 7 }

Step-by-step explanation:

Substitute the values of x from the domain into the relation to obtain the corresponding values of y , that is the range

x = - 1 : y = 3(- 1)² + 4(- 1) = 3(1) - 4 = 3 - 4 = - 1

x = 0 ; y = 3(0)² + 4(0) = 0 + 0 = 0

x = 1 : y = 3(1)² + 4(1) = 3 + 4 = 7

range is { - 1, 0, 7 }