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AfilCa [17]
3 years ago
9

Giving brainliest.. and 25 points

Mathematics
1 answer:
siniylev [52]3 years ago
5 0

Answer:

Alright well the simplified system is arbitrary solution of the original system of equation

a1 = - 15

an = - 15/4 Hope this helps have nice day :)

Step-by-step explanation:


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40 POINTS is (4,7) a solution of equations? Explain your answer 2x+4y=36 3x-4y=-6
dsp73
<span>2x + 4y = 36
3x - 4y = -6
--------------add
5x = 30 
  x = 6

</span>2x+4y=36 
2(6)+4y=36 
12 + 4y = 36
4y = 24
  y = 6

answer
<span>(6, 6) is a solution of equations
</span><span>(4,7) is NOT a solution of equations</span>
6 0
3 years ago
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Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi
Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

            =0.69937\\\approx0.70

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0
3 years ago
[100+(586+40/10)]/5&lt;19
Ksivusya [100]
Use PEMDAS.  So it would then simplify to [100+(586+4)]/5<19 then continueing that it would be [100+590]/5<19 and then 690/5<19 which finally will be 138<19 and that is a valid statement
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If a person ran 1/2 of a mile in 1/10 of an hour. How far will the person run in one (1) hour?
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Step-by-step explanation:

In 1/10 of 1hr = 1/2 mile

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It says, he can run 5 miles in 1 hour

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If A=750+135N; and B=485N, then A+B=
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