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3 years ago

Math problems help me with them giving 40 points and brainly!

Mathematics

2 answers:

Goshia [24]3 years ago

5 0

Answer:

it's 44.25%

Step-by-step explanation:

Plz mark as brainliest and follow me plz

marissa [1.9K]3 years ago

3 0

Answer:

Step-by-step explanation:

its additive identity

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A researcher conducted a hypothesis test to see if students on average spend more than 1 hour per homework assignment. The level

grandymaker [24]

Answer:

a. True

Step-by-step explanation:

By ∝= 5% we mean that there are about 5 chances in 100 of incorrectly rejecting a true null hypothesis. To put it in another way , we say that we are 95% confident in making the correct decision.

In the given question the null hypothesis is

H0: u ≤ 1 hour and Ha: u > 1 hour

So there is a 5% chance that the erroneous conclusion will be made that students spend on average more than 1 hour per assignment.

The given statement is true.

5 0

2 years ago

The mean preparation fee H&R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t

astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)= $\frac{ME*\sqrt{N}}{s }$ where

Me is the margin of error from the mean

s is the standard deviation of the population

N is the sample size

z(p)= $\frac{8*\sqrt{30}}{50 }$ ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

z(p)= $\frac{8*\sqrt{50}}{50 }$ ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

z(p)= $\frac{8*\sqrt{100}}{50 }$ ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

Minimum required sample size for 0.95 probability is

N≥ $(\frac{z*s}{ME} )^2$ where

N is the sample size

z is the corresponding z-score in 95% probability (1.96)

s is the standard deviation (50)

ME is the margin of error (8)

then N≥ $(\frac{1.96*50}{8} )^2$ ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0

3 years ago

A kennel is moving 160 dogs to a new facility each dog has its own crate the facility manager rents 17 trucks each truck holds 9

mina [271]

This will only be able to hold 153 dogs in total. He will need 1 additional truck to hold the last 7 dogs.

4 0

2 years ago

Anyone help me pls,find the area of each figure(All lines meet at right angles.)

baherus [9]

Answer:

The Area of the required figure is $315\:cm^2$

Step-by-step explanation:

$Area = (21\times 7)+(14\times 7) + (7\times 10)\\\\=147+98+70\\\\=315$

Best Regards!

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3 years ago

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