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3 years ago

Adding negative numbers –8 + 8 =

Mathematics

1 answer:

-BARSIC- [3]3 years ago

5 0

The answer would be 0

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Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$

Comparing equations (A) and (B), we have

$5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.$

Thus,

$AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.$

8 0

3 years ago

Which property is demonstrated below? (b·c)d=b(c·d) A. associative property B. distributive property C. commutative property D.

Snezhnost [94]

Answer:

associative

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Question 1= Can Kayla conclude that ∆ABC and ∆EDC are similar? Why or why not?

klasskru [66]

We know that 1 side is 100 and 1 angle is 90 degrees
we would need at least 1 more angle or 1 more side length to say that they are similar

no
but, if we asssume that DCB is a straignt line, then we can say that they are similar

2. if we say taht they are similar then DE=AB, so then 175=DE=AB

7 0

2 years ago

What is .65% of 160? show your work?

photoshop1234 [79]

65/100 ×160 =104 is the answer

7 0

3 years ago

Circle X with a radius of 6 units and circle Y with a radius

asambeis [7]

Answer:

Option C.

Step-by-step explanation:

It is given that radius of circle X is 6 units and radius of circle Y is 2 units.

Here, circle Y is smaller and circle X is larger.

$\text{Scale factor}=\dfrac{\text{Radius of circle X}}{\text{Radius of circle Y}}$

$\text{Scale factor}=\dfrac{6}{2}$

$\text{Scale factor}=3$

If we translate the circles so they share a common center point, and after that we dilate circle Y by a scale factor of 3, then we get circle which is equal to circle X.

We know that, after dilation the figure and its image are similar.

Hence, we can say that both circles are similar.

Therefore, the correct option is C.

8 0

2 years ago