Answer A. 15 glad to help
Answer:
Explanation:
<u>1) Calculate the volume of the water in the tank.</u>
- Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²
- Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ft
- Volume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.
<u>2) Calculate the weight of 21 ft³ of water.</u>
Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:
- 62.4 lb / 1 ft³ = x / 21 ft³
Solve for x:
- x = 21 ft³ × 64 lb / ft³ = 1,310.4 lb.
So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.
Answer:$8,000
Step-by-step explanation:
YEah im too lazy to say hiow i sovled jt
Because 4x2 = 8, so 4x7=28, then you times 28 by 2 which equals 56 and 8x7=56
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Answer:</h2>
<h2>
cos theta= adjacent side/ hypotenuse</h2><h2 /><h2>
cos theta= adjacent side/ hypotenusecos 36= x/8</h2><h2 /><h2>
cos theta= adjacent side/ hypotenusecos 36= x/8√5+1/4 = x/8</h2><h2 /><h2>
cos theta= adjacent side/ hypotenuse </h2>
cos 36= x/8√5+1/4 = x/8
4.7 is the approximate answer