The grams of glucose are needed to prepare 400g of a 2.00%(m/m) glucose solution g is calculated as below
=% m/m =mass of the solute/mass of the solution x100
let mass of solute be represented by y
mass of solution = 400 g
% (m/m) = 2% = 2/100
grams of glucose is therefore =2/100 = y/400
by cross multiplication
100y = 800
divide both side by 100
y= 8.0 grams
true, it has zero nuetrons which easily makes it more simple then the rest
To find the atomic mass, multiply the individual atomic masses with their relative abundances and add them up.
10.012*0.1991 + 11.009*0.8009 = 10.810 amu (5 s.f.)
Element X is Boron.
