Answer: come on man its not that hard
Explanation:
Answer:
At 0.58 L of 0.540 M NaOH solution contain 12.5 g NaOH.
Explanation:
Given data:
At volume = ?
Mass of NaOH = 12.5 g
Molarity of solution = 0.540 M
Solution:
First of all we will calculate the number of moles of sodium hydroxide.
Number of moles = mass/molar mass
Number of moles = 12.5 g / 40 g/mol
Number of moles = 0.3125 mol
Volume of NaOH:
Molarity = number of moles / volume in L
Now we will put the values.
0.540 M = 0.3125 mol / volume in L
volume in L = 0.3125 mol / 0.540 mol/L
volume in L = 0.58 L
Answer:
The level of toxins in solutions
Answer:
The volume of the sample of the gas is found to be 12.90 L.
Explanation:
Given pressure of the gas = P = 1.10 atm
Number of moles of gas = n = 0.6000 mole
Temperature = T = 288.15 K
Assuming the volume of the gas to be V liters
The ideal gas equation is shown below

Volume occupied by gas = 12.90 L