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MAXImum [283]
3 years ago
5

If R is the midpoint of QS , find QS (QR = 5x-3 and RS =21-x)

Mathematics
2 answers:
Finger [1]3 years ago
3 0

Answer:

QS is 34

Step-by-step explanation:

We find x first. We set each side equal to each other to do so.

5x-3=21-x

6x=24

x=4

Next we find QS value. We add each side.

5x-3+21-x

4x+18

Then we plug in x to find numeric value.

4(4)+18

34

Arlecino [84]3 years ago
3 0

Answer:

QS is 34

Step-by-step explanation:

R is the midpoint of QS

So, QR= RS

(QR = 5x-3 and RS =21-x)

QR= RS

Plug in QR  and RS

5x-3=21-x

Add x on both sides

6x-3= 21

Add 3 on both sides

6x= 24

Divide by 6 on both sides

x= 4

QS= QR+RS

QS=5x-3+21-x

QS=4x+18

Plug in 4 for x

QS=4(4)+18=34

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vladimir1956 [14]

Answer:

(2b+3) (b+7)

Step-by-step explanation:

2b²+17b+21

2b²+14b+3b+21

2b(b+7) + 3(b+7)

(2b+3) (b+7)

6 0
2 years ago
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A marble is drawn from a bag containing 3 red marbles and 2 blue marbles and a number cube with faces numbered 1 through 6 is to
lorasvet [3.4K]
Find sample space
step 1: pick one marbles from 5. there are 5 ways (5C1)
step 2: toss a cube one time, 1-6. there are 6 ways (6C1)

total ways (sample space) = 5x6 = 30
... multiplication rules

find event
step 1: pick one blue marbles from 2. there are 2 ways (2C1)
step 2: toss a cube one time, get only 1 or 2. there are 2 ways (2C1)

total ways for event = 2x2 = 4

p(event) = n(event)/n(sample space) = 4/30
5 0
3 years ago
An athlete trains on a circular track of radius 40 m and jogs 10 laps each day, 5 days a week. How far does he jog each week? Ro
mariarad [96]
Length of a circle=2πr
r=40 m
Length of the circular track=2*π*40m=80π m.

The athelete jogs each day 10 laps
1 lap-------------------80π m
10 laps-------------   x
x=(10 laps * 80π m) / 1 lap=800π m

Calculate how far he jog eache week (5 days).
1 day------------------800π m
5 days----------------   x
x=(5 days*800π m)/1day=4000π m=4000m * 3.141592...≈12566,37 m

solution: 12566 m

5 0
3 years ago
Write the equation of a parabola with focus at (1,-4) and a directrix at X=2
konstantin123 [22]

Answer:

The equation of a parabola is

x =  \frac{1}{4(f - h)} (y - k) ^{2}  + h

Step-by-step explanation:

(h,k) is the vertex and (f,k) is the focus.

Thus, f = 1, k = −4.

The distance from the focus to the vertex is equal to the distance from the vertex to the directrix: f - h = h - 2.

Solving the system, we get h = 3/2, k = -4, f = 1.

The standard form is:

x =  -  \frac{y ^{2} }{2}  - 4y -  \frac{13}{2}

The general form is:

2x +  {y}^{2}  + 8y + 13 = 0

The vertex form is:

x =  -  \frac{(y + 4) ^{2} }{2}  +  \frac{3}{2}

The axis of symmetry is the line perpendicular to the directrix that passes through the vertex and the focus: y = -4.

The focal length is the distance between the focus and the vertex: 1/2.

The focal parameter is the distance between the focus and the directrix: 1.

The latus rectum is parallel to the directrix and passes through the focus: x = 1.

The length of the latus rectum is four times the distance between the vertex and the focus: 2.

The eccentricity of a parabola is always 1.

The x-intercepts can be found by setting y = 0 in the equation and solving for x.

x-intercept:

( -  \frac{13}{2}  \: ,0)

The y-intercepts can be found by setting x = 0 in the equation and solving for y.

y-intercepts:

(0, - 4 -  \sqrt{3)}

(0, - 4 +  \sqrt{3)}

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2 years ago
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Answer:

y=3

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3y -9+9 = 0+9

3y =9

Divide by 3

3y/3 = 9/3

y =3

4 0
3 years ago
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