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2 years ago

Can anyone help me out with proofs ? If B is midpoint of AC and D is the midpoint of CE prove BD is parallel AE.

Mathematics

2 answers:

Luden [163]2 years ago

7 0

Could you include a picture of the question and diagram

bearhunter [10]2 years ago

5 0

Um I don’t really know

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(a) Are triangles the congruent? Write the congruency statement.

Maru [420]

Answer:

Part A) Yes , the triangles are congruent

Part B) The side-angle-side (SAS) theorem

Part C) The perimeter of ∆PQR is $17\ ft$

Step-by-step explanation:

Step 1

we know that

The side-angle-side (SAS) theorem, states that: If two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle, the triangles are congruent.

so in this problem

Traingle PQR and Triangle STU are congruent by the SAS Theorem

because

m<PQR=m<STU -------> included angle

PQ=TS

QR=TU

Step 2

Find the value of y

we know that

If the triangles are congruent

then

The corresponding sides are equal

$PR=SU$

substitute

$(3y-2)=(y+4)$

$(3y-y)=(2+4)$

$(2y)=(6)$

$y=3\ ft$

$PR=3y-2=3(3)-2=7\ ft$

$SU=y+4=(3)+4=7\ ft$

$PR=SU$

Step 3

Find the perimeter ∆PQR

Remember that

The perimeter of ∆PQR is equal to the perimeter ∆STU

The perimeter is equal to

$P=PQ+QR+PR$

substitute the values

$P=4+6+7=17\ ft$

6 0

3 years ago

Verify that (a+b)+c = a+ (b+c) by taking a = -8 , b = (-8/11) , c = (-8/12)

gogolik [260]

Answer:

Step-by-step explanation:

$(-8+-\frac{8}{11} ) + (-\frac{8}{12}) = -\frac{96}{11} + (-\frac{2}{3}) = -\frac{288 + 22}{33}) = -\frac{310}{33}\\ (-8) + (-\frac{8}{11} + (-\frac{2}{3})) = (-8) + (-\frac{46}{33})= -\frac{310}{33}$