F(x)= -2x^2what is the vertex of this and/or how do you find the vertex??
1 answer:
Answer:
(0,0)
Step-by-step explanation:
x value of vertex = -b/2a
ax^2+bx+c
-2x^2+0x+0 sinc you have no value of b & c in your quadratic function
-b = 0
2a = (2)(-2)
-b/2a = (0/-4) = 0
x value of the vertex = 0
plug 0 in for all values of x in the function to find y coordinate value
-2(0)^2 = 0
(x,y) = (0,0)
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