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Mashcka [7]
3 years ago
11

Julie has 2 cherry lollipops, 4 lime lollipops, and 3 grape lollipops in a bag. She is going to select one lollipop, replace the

lollipop in the bag, and then select a second one. What is the probability that Julie will select a cherry lollipop and then a lollipop other than lime?
Mathematics
1 answer:
Reptile [31]3 years ago
5 0

Answer:

the answer is simple B 10/81

Step-by-step explanation:

You might be interested in
Gerald works 18 hours each week he earns $10 per hour how much Gerald earns in 1 week
Serga [27]

Answer:

This is much the same as the last one:

How many hours a week does he work?

18

Then give him his wages:

18*10=180

Presto!

Answer:$180

Step-by-step explanation:

6 0
3 years ago
4c+2=3c+5 what is the value of c
Grace [21]

Answer:

c = 3

Step-by-step explanation:

4c + 2 = 3c + 5

4c = 3c + 3

c = 3

4 0
3 years ago
Find the lengths of the sides of the triangle PQR. P(2, −3, −4), Q(8, 0, 2), R(11, −6, −4) |PQ| = Incorrect: Your answer is inco
Aloiza [94]

Answer:

the length PQ is 9 units,the length QR is 9 units,the length PR is 9.48 units,the triangle is not a right triangle,this is a isosceles triangle

Step-by-step explanation:

Hello, I think I can help you with this

If  you know two points, the distance between then its given by:

P1(x_{1},y_{1},z_{1} ) \\P2(x_{2},y_{2},z_{2})\\\\d=\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1}  )^{2}+(z_{2}-z_{1} )^{2} }

Step 1

use the formula to find the length PQ

Let

P1=P=P(2, −3, −4)

P2=Q=Q(8, 0, 2)

d=\sqrt{(8-2)^{2} +(0-(-3))^{2}+(2-(-4))^{2}} \\ d=\sqrt{(6)^{2} +(3)^{2}+(6 )^{2}}} \\d=\sqrt{36+9+36}\\d=\sqrt{81} \\d=9\\

the length PQ is 9 units

Step 2

use the formula to find the length QR

Let

P1=Q=Q(8, 0, 2)

P2=R= R(11, −6, −4)

d=\sqrt{(11-8)^{2} +(6-0))^{2}+(-4-2 )^{2}}  \\\\\\d=\sqrt{(3)^{2} +(6)^{2}+(-6 )^{2}}} \\d=\sqrt{9+36+36}\\d=\sqrt{81} \\d=9\\

the length QR is 9 units

Step 3

use the formula to find the length PR

Let

P1=P(2, −3, −4)

P2=R= R(11, −6, −4)

d=\sqrt{(11-2)^{2} +(-6-(-3)))^{2}+(-4-4 )^{2}}  \\\\\\d=\sqrt{(9)^{2} +(-6+3)^{2}+(-4-(-4) )^{2}}} \\d=\sqrt{81+9+0}\\d=\sqrt{90} \\d=9.48\\

the length PR is 9.48 units

Step 4

is it a right triangle?

you can check this by using:

side^{2} +side^{2}=hypotenuse ^{2}

Let

side 1=side 2= 9

hypotenuse = 9.48

Put the values into the equation

9^{2} +9^{2} =9.48^{2}\\ 81+81=90\\162=90,false

Hence, the triangle is not a right triangle

Step 5

is it an isosceles triangle?

In geometry, an isosceles triangle is a type of triangle that has two sides of equal length.

Now side PQ=QR, so this is a isosceles triangle

Have a great day

3 0
3 years ago
What is the value of x? <br> A. 20 <br> B. 35<br> C. 60<br> D. 70
Svetlanka [38]
A. 20. plug 20 in to both equations and they will be equal to eachother
6 0
3 years ago
if <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B3%7D%20-%20%5Cfrac%7B1%7D%7B2%7Dx%20" id="TexFormula1" title="f
Dimas [21]

Answer:

\large\boxed{(f+g)(x)=2x^2+\dfrac{1}{2}x+4\dfrac{1}{3}}

Step-by-step explanation:

(f+g)(x)=f(x)+g(x)\\\\\text{We have}\\\\f(x)=\dfrac{1}{3}-\dfrac{1}{2}x,\ g(x)=2x^2+x+4.\\\\\text{Substitute:}\\\\(f+g)(x)=\left(\dfrac{1}{3}-\dfrac{1}{2}x\right)+(2x^2+x+4)\\\\=\dfrac{1}{3}-\dfrac{1}{2}x+2x^2+x+4\qquad\text{combine like terms}\\\\=2x^2+\left(-\dfrac{1}{2}x+x\right)+\left(\dfrac{1}{3}+4\right)\\\\=2x^2+\dfrac{1}{2}x+4\dfrac{1}{3}

6 0
3 years ago
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