If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
Answer:
(½x+½y)²=6
Step-by-step explanation:
x^2 + y^2 = 14, xy=5
(A+B)^2=A^2 +2AB+B^2... (*)
(1/2x+1/2y)^2 =(*)
(1/2x)^2 +2(1/2x)(1/2y)+(1/2y)^2 =
1/4x^2 +1/2xy+1/4y^2=
1/4(x^2 +y^2) +1/2(xy)=
1/4*14+1/2*5=
14/4+5/2=
14/4+10/4=
24/4=6
let me know if I'm wrong.
1.04 kilograms
1 gram = .001 kilogram
2x520= 1040
1040 x .001 = 1.04 kilograms
Hey there!!
Let's take the length of the bigger piece as x inches
Then, the length of the smaller piece would be x - 8 inches
The sum of these lengths would be 54 inches
... x + x - 8 = 54
... 2x - 8 = 54
... Add 8 on both sides
... 2x = 62
... Divide 2 on both sides
... x = 31
Hence, the length of the bigger piece = 31 inches
The length of the smaller piece would be = 31 - 8 = 23 inches
Hope my answer helps!!
