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4 years ago

Explain why an ecological pyramid is smaller at the top then the bottom

1 answer:

3 0

The ecological pyramid is smaller at the top due to the lower amount of species to fit into the category (diversity is decreased, and the higher, the more suppressed the energy is in the animals/species).

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In eukaryotic cells, the message from the DNA must be removed from the nucleus before it can be read and used to make proteins.

Veronika [31]

Answer:

Protein production in prokaryotes begins even before the completion of transcription. This means that ribosomes attach to the mRNA being generated even before transcription process is terminated. Therefore translation occurs in concurrence with transcription. This is because there is no definitive boundary between the nucleoid and cytoplasm.

In eukaryotic cells, the nucleus is separated from the cytoplasm by the nuclear membrane. This means transcription has to complete before the translation of proteins occurs. This is because the ribosomes are located in the cytoplasm while the DNA is in the nucleus.

This difference is part of the reason prokaryotic cells are able to respond really fast to an environmental stimuli as compared to eukaryotes. Remember in addition mRNA in prokaryotes do not need splicing (as required in eukaryotes) adding to quick protein production.

Learn More:

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3 0

3 years ago

Calculate the final concentration of BSA in the problems below using the formula

Rudiy27

Answer:

A. $C_2=1.5\frac{mg}{mL}$

B. $C_2=0.075\frac{mg}{mL}$

C. $C_2=0.01\frac{mg}{mL}$

D. $C_2=0.001\frac{mg}{mL}$

Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

$C_2=\frac{C_1V_1}{V_2}$

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

$C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}$

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

$C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}$

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

$C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}$

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

$C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}$

Best regards.

7 0

3 years ago

How does a pluripotent cell differ from a totipotent cell

12345 [234]

Answer:

Pluripotent cells can be almost anything they want to be while totipotent are for ex, like zygotes. They can give rise to placenta and embryo

4 0

3 years ago

Read 2 more answers

Biological process <br> dna y mrna z protien

Setler79 [48]

Here, the letter "Y" refers to transcription, while the letter "Z" refers to translation.

<h3>What do you mean by Transcription?</h3>

Transcription may be defined as a biological process through which a cell makes a copy of RNA (mRNA) from a segment of DNA. It occurs in the nucleus of the cell.

Translation may be defined as a biological process through which a cell makes proteins with the help of genetic information carried by mRNA. It occurs in the cytoplasm of the cell.

Therefore, here, the letter "Y" refers to transcription, while the letter "Z" refers to translation.

To learn more about Transcription, refer to the link:

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7 0

2 years ago

kim has a bag of yo-yos. Some of the yo-yos are red. The rest are yellow. The ratio of the number of red yo-yos to the number of

photoshop1234 [79]

Answer:

5 + 9 = total = 14

14 = total = b

5/14 of them are red 9/14 are yellow

yellow - red = 9 / 14b - 5 / 14b = 4 / 14b = 2 / 7b there are ( 2/7 ) b more yellow than red CAUSED apologiabiology .

Hope this helps ✌️

3 0

4 years ago

Read 2 more answers