All categories

4 years ago

Is √2/3 a rational or irrational

Mathematics

2 answers:

scoundrel [369]4 years ago

4 0

sqrt(2/3) = 0.816496

since it is a decimal with no repeating numbers it would be irrational

stiv31 [10]4 years ago

3 0

Irrational because you would get a decimal

You might be interested in

The stalemate in the western front began after Germany failed to quickly defeat

Andrei [34K]

Answer:

B) France

Step-by-step explanation:

The stalemate in the western front began after Germany failed to quickly defeat 'France'

5 0

3 years ago

Read 2 more answers

Write two numbers that multiply to the value on top and add to the value on the bottom.

Nastasia [14]

Answer:

1 and 19

Step-by-step explanation:

I believe this is a factoring problem.

Example:

If we have the equation x^2-2x-3

We can find two numbers that multiply to -3 that add to -2

The two numbers are -3 and 1

(x-3)(x+1)= So x=3 and x=1

8 0

3 years ago

Read 2 more answers

Someone plz help me here ;-; it’s due today! I have another due today plz help I have to redo this one cause I got one wrong ;-;

Alja [10]

Answer:

I think It is D

7 0

3 years ago

Read 2 more answers

A total of 603 tickets were sold for the school play. They were either adult tickets or student tickets. There was 53 more stude

pochemuha

The number of student tickets sold is half the total plus half the difference:
student tickets = (603 +53)/2 = 656/2 = 328

The number of adult tickets is 53 fewer, 275.

6 0

3 years ago

Read 2 more answers

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.

Therefore, the right answer is b. f(x) = 1/2(x + 11)^2 - 5

SECOND.

Translating 8 units to the right:

$g(x)=f(x-8) \\ \\ \therefore g(x)=(x-8)^2$

Then translating 1 unit down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x-8)^2-1$

As explained in the previous case, there are two factors 1/3 and 3, so we choose the first one.

Therefore, the right answer is a. g(x) = 1/3(x - 8)^2 - 1

7 0

3 years ago