Answer:
<em><u>263.76</u></em><em><u> </u></em><em><u>in</u></em><em><u>^</u></em><em><u>3</u></em>
VOLUME OF FIGURE=VOL.OF CONE+VOL.OF CYLINDER +VOL.OF HEMISPHERE
=(1/3×3.14×3×3×4)+(3.14×3×3×6)+(2/3×3.14×3×3×3)
=37.68+169.56+56.52
=263.76in^3
Answer: player number one
Step-by-step explanation:
Player number one starts with one and then he waits for player number two.
It doesnt matter what player number two makes, he needs to keep his multipliyer in two until player two pasess one millon/9 =111111.11 for the first time, then, he plays 9.
Answer:
Choice B is correct.
Explanation:
The given equation is -r+5(r+2)=-10
Put r=-5 into the above equation
-(-5)+5(-5+2)=-10
5+5(-3)=-10
5-15=-10
-10=-10
Right and left side of above equation is equal by putting r=-5 so it is true statement.
Answer:
34
Step-by-step explanation:
x - 9 = 25
x=25+9
x=34
<span>The height of Gateway Arch shown on the Missouri quarter is 630 feet or 7,560 inches. Find how many 4 inch stacks of quarters make up the height of the Gateway Arch. If there are 58 quarter in 4 inch stack o, how many quarters high is the arch? </span>
<span>Hence to find how many 4 inch stacks of quarters make up the height of the </span><span>Gateway Arch,
Since the Gateway Arch is 7560 then for every stack is 4 inches to find the stacks all in all, we just have to divide 7560 / 4 = 1890
Then, to find </span><span>how many quarters high is the arch,
58 quarter x 4 inch = 232 quarters high in inches.
</span>