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kicyunya [14]
4 years ago
8

Consider the diagram Lines AC and RS are A coplanar. B parallel. C perpendicular D skew.​

Mathematics
2 answers:
Tanzania [10]4 years ago
7 0

Answer: The answer is skew!

Step-by-step explanation:h

skelet666 [1.2K]4 years ago
3 0

Answer:skew, b

Step-by-step explanation:

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Simplify the expression (4x - 8y) - (11x - 3y + 6)
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tensa zangetsu [6.8K]
Answer: Choice D) 
The angle between the two vectors is approximately 71.6 degrees

----------------------------------------------
----------------------------------------------

Work Shown: 

Each time I write the word "dot" I mean "dot product". 

|u| = length of vector u
|u| = sqrt(u dot u)
|u| = sqrt(<8,4> dot <8,4>)
|u| = sqrt(8*8 + 4*4)
|u| = sqrt(64 + 16)
|u| = sqrt(80)
|u| = sqrt(16*5)
|u| = sqrt(16)*sqrt(5)
|u| = 4*sqrt(5)

-----------------------

|v| = length of vector v
|v| = sqrt(v dot v)
|v| = sqrt(<9,-9> dot <9,-9>)
|v| = sqrt(9*9 + (-9)*(-9))
|v| = sqrt(81+81)
|v| = sqrt(2*81)
|v| = sqrt(2)*sqrt(81)
|v| = sqrt(2)*9
|v| = 9*sqrt(2)

-----------------------

u dot v = <8,4> dot <9,-9>
u dot v = 8*9 + 4*(-9)
u dot v = 72-36
u dot v = 36

-----------------------

cos(theta) = (u dot v)/(|u|*|v|)
cos(theta) = (36)/(4*sqrt(5)*9*sqrt(2))
cos(theta) = (36)/(36*sqrt(10))
cos(theta) = 1/(sqrt(10))
cos(theta) = sqrt(10)/10
theta = arccos(sqrt(10)/10)
theta = 71.56505
which rounds to 71.6 when rounding to one decimal place (nearest tenth)

That's why the approximate answer is roughly 71.6 degrees

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3 years ago
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<h3>A television with a 5:4 screen shows an image with a ratio of 20:12 which creates a letter boxed image. What percent of the screen's area is occupied by the image?</h3>

Answer: d. 75% of the screen is occupied by the image  

Step-by-step explanation:

First we have to find a relation between image area and screen area.

Image area is the product of image dimensions.

Screen area is the product of screen dimensions.

We have to divide the major image dimension between the major screen dimension

Major image dim/Major screen dim = 20/5 = 4

Now we have to multiply this relation by the minor screen dimension

Minor screen dim x 4 = 4 x 4 = 16

Then we have found 5/4 = 20/16

Now we can calculate what percent of the screen area is occupied by the image area.

Major image dim x minor image dim/Major screen dim x minor screen dim

Since major image dim = major screen dim, we have:

Minor image dim/Minor screen dim = 12/16 = 0.75 = 75% of the screen

Answer: d. 75% of the screen is occupied by the image

\textit{\textbf{Spymore}}  

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