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kicyunya [14]
3 years ago
8

Consider the diagram Lines AC and RS are A coplanar. B parallel. C perpendicular D skew.​

Mathematics
2 answers:
Tanzania [10]3 years ago
7 0

Answer: The answer is skew!

Step-by-step explanation:h

skelet666 [1.2K]3 years ago
3 0

Answer:skew, b

Step-by-step explanation:

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Calculate the limit values:
Nataliya [291]
A) This particular limit is of the indeterminate form,
\frac{ \infty }{ \infty }
if we plug in infinity directly, though it is not a number just to check.

If a limit is in this form, we apply L'Hopital's Rule.

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Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_ {x \rightarrow \infty } \frac{( ln(x ^{2} + 1 ) ) '}{x ' }
So we take the derivatives and obtain,

Lim_ {x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ \frac{2x}{x^{2} + 1} }{1}

Still it is of the same indeterminate form, so we apply the rule again,

Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ 2 }{2x}

This simplifies to,

Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ 1 }{x} = 0

b) This limit is also of the indeterminate form,

\frac{0}{0}
we still apply the L'Hopital's Rule,

Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ (tanx)'}{x ' }

Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ \sec ^{2} (x) }{1 }

When we plug in zero now we obtain,

Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ \sec ^{2} (0) }{1 } = \frac{1}{1} = 1
c) This also in the same indeterminate form

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ ({e}^{2x} - 1 - 2x)'}{( {x}^{2} ) ' }

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ (2{e}^{2x} - 2)}{ 2x }

It is still of that indeterminate form so we apply the rule again, to obtain;

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ (4{e}^{2x} )}{ 2 }

Now we have remove the discontinuity, we can evaluate the limit now, plugging in zero to obtain;

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = \frac{ (4{e}^{2(0)} )}{ 2 }

This gives us;

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } =\frac{ (4(1) )}{ 2 }=2

d) Lim_ {x \rightarrow +\infty }\sqrt{x^2+2x}-x

For this kind of question we need to rationalize the radical function, to obtain;

Lim_ {x \rightarrow +\infty }\frac{2x}{\sqrt{x^2+2x}+x}

We now divide both the numerator and denominator by x, to obtain,

Lim_ {x \rightarrow +\infty }\frac{2}{\sqrt{1+\frac{2}{x}}+1}

This simplifies to,

=\frac{2}{\sqrt{1+0}+1}=1
5 0
3 years ago
What is the amount of change from 20 to 36
OlgaM077 [116]

Answer:

16

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Please help will give brainliest to right answer
tatuchka [14]

Answer:

The answer is 138cm²

Step-by-step explanation:

(10x7)+(10x4)+(7x4) The formual is (LxW)+(LxH)+(WxH) please brainliest me

7 0
3 years ago
The number of new customers n that visit a dry cleaning shop in one year is directly related to the
Ipatiy [6.2K]

Answer:

$15,264 cost amount on new advertising.

Shown as new equation that includes (original + new customer base)

n3=15264a

Step-by-step explanation:

First we have to find original amount of customers as 3 represents a multiple of n

n3=13824a

n3 means n x 3 then customer base is one third

= 1/3 x 13,824  = 4608 original customers per year

= 4608 original customers +480 new customers

4608 + 480 = 5088 total orig+initial  customers

5088 x 3 = 15264 cost

= ($)15,264 cost

new equation

n3=15264a

4 0
3 years ago
Which is the best estimate for the value of point C?
Georgia [21]
Hello,

We may suppose that abscisse of C is 21 or 22

As √484=22

Answer D: \sqrt{484}
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3 years ago
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