The equation y = 1/3x - 2 passes through the diagonals of ZDRN
<h3>How to determine the end result?</h3>
The points are given as:
Z = (-3, -1)
D= (3, -1)
R = (3, -3)
N = (-3, -3)
The equation of the line is given as:
y = 1/3x - 2
When the points and the line equation are plotted in a graph on the same coordinate (see attachment), we can see that the equation y = 1/3x - 2 passes through the points Z = (-3, -1) and N = (-3, -3)
These points are the diagonals of the shape formed by the four points
Hence, the equation y = 1/3x - 2 passes through the diagonals of ZDRN
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The answer is 246 units²
<span>Surface area= 2(lw + lh + wh)</span>
Answer:
Step-by-step explanation:
Given that vector a has starting point (2,3) and end point (5,7)
Direction ratios of AB = (5-2, 7-3) = (3,4)
Magnitude =
a) Starting point (0,2)
Distance= 5 units from (0,2) and direction ratios (3,4)
So the point will be of them (0+3t, 2+4t)
Distance = 5t units. So t =1
So point is (3,6)
b) When starting point =(0,5)
End point with same direction would be
(0+3, 5+4) = (3,9)
36% in decimal from it .36
172.80 + .36 = 173.16
So original price was 173.16
f(x) means x = -2 if you multiply 1/2 by -2 you get -1