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OverLord2011 [107]
3 years ago
11

Plz help me !!!!!!!!

Mathematics
1 answer:
Dovator [93]3 years ago
7 0

Answer:   c) -1372

<u>Step-by-step explanation:</u>

\sqrt[3]{2x} +6=-8\\\\\sqrt[3]{2x} =-14\\\\(\sqrt[3]{2x})^3 =(-14)^3\\\\2x=-2744\\\\\boxed{x=-1372}

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In March, Derrick had $25.50 in credit card debt.
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Answer:

-20.50?

Step-by-step explanation:

I think you said he added 5 dollars in his account which would get some of his debt removed. But he would still have a remaining -20.50 dollars to get rid of.

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5 - Numbers from 1 to 50 are written on a piece of paper and dropped into a box. A paper is chosen at random
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Answer:

1 out of a 50% chance

Step-by-step explanation:

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A survey of 125 randomly selected teens ages 13 to 16 found that 33 of them play soccer, 27 of them play basketball, 24 of them
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34. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
skad [1K]

Answer:

The linear equation for the line which passes through the points given as (-1,4) and (5,2), is written in the point-slope form as $y=\frac{1}{3} x-\frac{13}{3}$.

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-1,4) and (5,2).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-1,4) and (5,2). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 2&4 for $y_{2}$ and $y_{1}$ respectively, and $5 \&-1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

m=\frac{2-4}{5-(-1)}$\\ $m=\frac{-2}{6}$\\ $m=-\frac{1}{3}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-1 for $x_{1}$, and 4 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

y-4=-\frac{1}{3}(x-(-1))$\\ $y-4=-\frac{1}{3}(x+1)$\\ $y-4=-\frac{1}{3} x-\frac{1}{3}$

Step 3 of 3

Simplify the equation further.

Add 4 on each side of the equation $y-4=\frac{1}{3} x-\frac{1}{3}$, and simplify as follows,

y-4+4=\frac{1}{3} x-\frac{1}{3}+4$\\ $y=\frac{1}{3} x-\frac{1+12}{3}$\\ $y=\frac{1}{3} x-\frac{13}{3}$

This is the required linear equation.

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2 years ago
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miv72 [106K]

Answer:

A = ...-5π ,-4π ,-3π, -2π, -π, 0, π, 2π, 3π, 4π, 5π....

A = {x ∈ N, πx}

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