Let's assume that the statement "if n^2 is odd, then is odd" is false. That would mean "n^2 is odd" leads to "n is even"
Suppose n is even. That means n = 2k where k is any integer.
Square both sides
n = 2k
n^2 = (2k)^2
n^2 = 4k^2
n^2 = 2*(2k^2)
The expression 2(2k^2) is in the form 2m where m is an integer (m = 2k^2) which shows us that n^2 is also even.
So this contradicts the initial statement which forces n to be odd.
Answer:
equaly alike.
Step-by-step explanation:
well, let's check the graph, and use two points off of it..hmmmm it passes through (4, 0) and it also passes through (0, -4).
so, what would be the equation of a line that passes through those two points?
keeping in mind that
standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient

Answer:
the answer is 19
Step-by-step explanation:
8+6=14
14+5=19