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3 years ago

How do you solve algebra

Mathematics

2 answers:

Amiraneli [1.4K]3 years ago

4 0

Answer:

FORMULAS 

a (b + c) = ab + ac

(a + b)2 = a2 + 2ab + b2

(a − b)2 = a2 − 2ab + b2

(a + b)(a − b) = a2 − b2

Making Groups ( factorize four terms)

2x² - 2x + 5x - 5

= 2x (x - 1) + 5(x - 1)

= (x - 1) (2 x + 5)

Evaluation of algebraic expressions 

The process of replacing the variables in an expression with the numerical values and simplifying it is known as evaluating an algebraic expression. Following order of operation is used to evaluate an algebraic expression;

1. Perform the operations inside a parenthesis first

2. Then exponents

3. Then multiplication and division, from left to right

4. Then addition and subtraction, from left to right

Hope this will help you if you need more help about algebra free to ask i will try ! 

because algebra is big enough 

amid [387]3 years ago

3 0

Answer:

it is gard to explain so i will give you link you can get help there.

Step-by-step explanation:

https://www.ipracticemath.com/learn/algebra/algebra_methods_for_solution

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A bag contains 5 red marbles, 3 blue marbles and 6 green marbles. If three marbles

Zanzabum

Answer:

333/364 or 0.915

Step-by-step explanation:

Red marbles = 5

Blue marble = 3

Green marble = 6

Total number of marbles in the bag = 5 + 3 6 = 14

1. The first draw, we have 5 red marbles out of 14 marbles = 5 / 14

Now we have 13 marbles left of which 4 are red.

2. Second draw, we have 4 red marbles and a total of 13 marbles = 4 / 13

3. Third draw, we have 12 marbles left and 3 are red. = 3 / 12 = 1 / 4

Probability of drawing all the red marbles = (5 / 14) * (4 / 13) * (1 / 4) = 333 / 364 = 0.9148

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3 years ago

Arnold had three pieces of different colored strings that are all the same length Arnold cut the blue string and a two equal sid

Ivanshal [37]

The answer is six equal sized links because two, three, and six, are all factors of six.

6 0

3 years ago

Read 2 more answers

The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,608 kilowatt hours (kWh

Marat540 [252]

Answer:

The calculated value Z = 1.4460 < 1.96 at 0.05 level of significance.

The null hypothesis is accepted

A local power company believes that residents in their area use more electricity on average than EIA's reported average

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 10,608 kWh of electricity this year.

Given that the size of the sample n = 187

Given that mean of sample x⁻ = 10737 kWh

The Standard deviation of the Population = 1220kWh

Level of significance = 0.05

The critical value (Z₀.₀₅)= 1.96

Step(ii):-

Null Hypothesis: H₀:μ > 10608 kWh

Alternative Hypothesis: H₁: μ < 10608kWh

Test statistic

$Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{10737- 10608 }{\frac{1220}{\sqrt{187} } }$

Z = 1.4460

Final answer:-

The calculated value Z = 1.4460 < 1.96 at 0.05 level of significance.

The null hypothesis is accepted

A local power company believes that residents in their area use more electricity on average than EIA's reported average.

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3 years ago

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Diano4ka-milaya [45]

Answer:

9/22

Step-by-step explanation:

First:

Convert any mixed numbers to fractions.

Then your initial equation becomes:

−9/4 ÷ −11/2

Applying the fractions formula for division,

=−9×2 divided by 4×−11

=−18/−44

Simplifying -18/-44, the answer is

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