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malfutka [58]
3 years ago
12

A plane rises from take off and flies at an angle 11° with the horizontal runway. When it has gained 750 feet find the distance

to the nearest foot the plane has flown
Mathematics
1 answer:
kogti [31]3 years ago
7 0

Answer:

D=3930.632298 \approx 3930.6miles

Step-by-step explanation:

From the question we are told that

Angle  \theta=11\textdegree

Height of plane h  =750feet

Generally the equation for the total distance flown is mathematically given by

D=\frac{h}{sin\theta}

D=\frac{750}{sin11}

Therefore total distance flown is

D=3930.632298 \approx 3930.6miles

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Step-by-step explanation:

we know that

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Remember that an equilateral triangle has three equal sides and three equal interior angles

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