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rosijanka [135]
3 years ago
14

A recipe calls for 2 1/2 Cups of flour and four eggs. If only three eggs are used, how many cups of flour should be used? Give y

our answer as a mixed number in simplest form.
Mathematics
1 answer:
MAXImum [283]3 years ago
8 0

Answer:

Step-by-step explanation: write the equation in the form of a proportion

2 1/2 is to 4 as something is to 3

2 1/2 / 4 = x/3

Then, cross multiply 2 1/2 x 3 or

5/2 x 3/1 = 15/2

Next cross multiply 4•X= 4X

Write as 4X = 15/2

Divide both sides by 4.

4X/ 4 = 15/2 /4

x = 15/2÷ 4/1

Divide by changing the sign to multiplication and inverting 4/1 to 1/4 like this:. 15/2. × 1/4= 15/8

Finally, 15/8 simplifies to 1 7/8 cups

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6 0
3 years ago
Read 2 more answers
Emmanuel is going on a trip with his family! His family leaves his apartment at 9:25 a.M. If it takes emmanuel 3 hours and 22 mi
Pavlova-9 [17]

Answer:

12:47 PM

Step-by-step explanation:

Add 3 to 9 and add 22 to 25.

Make sure your answer is PM and not AM

6 0
3 years ago
4) A garden is in the shape of a square with a perimeter of
Leni [432]

Answer:

It costs $154.88 to build the fences.

Step-by-step explanation:

Perimeter of square = 4 \times Side

We are given that A garden is in the shape of a square with a perimeter of  56 feet.

So,4 \times side = 56

Side =\frac{56}{4}=14 feet

So, Side of square park = 14 feet

One fence is around the perimeter of the garden, whereas the second fence is 2 feet from the first fence on the outside.

Outer length = 14+2+2=18 feet

So, Perimeter of outer fence = 4 \times side = 4 \times 18 = 72 feet

Cost of fencing 1 foot = $1.21

Cost of fencing 56 feet =56 \times 1.21=67.76

Cost of fencing 72 feet = 72 \times 1.21=87.12

Total cost = 67.76+87.12=154.88

Hence It costs $154.88 to build the fences.

7 0
3 years ago
Is the following benefit true for credit cards, debit cards, both or neither?
Mars2501 [29]

Answer:

too what i know no they don't answer=(false)

Step-by-step explanation:

hope this helps if it is wrong then you know it was true..

5 0
3 years ago
A 2-kg object is fired from a cannon at a 30º angle wrt to the horizontal. the initial speed is 35 m/s. how high will the object
kompoz [17]
     <span> You have :
----------------

v0 = 35 m/s

B = angle of elevation = 30 deg

a suby = - g

v suby0 = ( v0 ) ( sin B )

v suby0 = ( 35 m/s ) ( sin 30 ) = 17.5 m/s

At maximum height :
------------------------------

v suby = vy* = 0.0

t = t*

y = ymax = y*

Basic kinematics gives :
-------------------------------------

a suby = dv suby / dt = -g ------> dt = dv suby /a suby

v suby = dy/dt ------> dt = dy / vsuby

dt = dv suby / a suby = dy / v suby

( v suby ) ( d v suby) = ( a suby ) dy = ( -g ) dy

Now integrate and get :
-----------------------------------

( v suby* )^2 - ( v suby0)^2 ( 1/2 ) = ( -g ) ( ymax )

ymax = [ ( v suby0 )^2 - ( v suby* )^2 ] / [ ( 2 ) ( g ) ]

ymax = ( 17.5 m/s )^2 - ( 0.0 m/s )^2 ] / [ ( 2 ) ( 9.807 m/s^2 ) ]

ymax = 15.6 m <------------------

Check the result:
--------------------------

t* = v suby0 / g = ( 17.5 m/s ) / ( 9.807 m/s^2 ) = 1.784 s

y* - y0 = ( v suby0 ) ( t* ) - ( g/2 ) ( t* )^2

y* = ( 17.5 m/s ) ( 1.784 s ) - ( 9.807 m/s^2 / 2 ) ( 1.784 s )^2

y* = ymax = 31.23 m - 15.61 m = 15.6 m

The ymax values agree.</span>
6 0
3 years ago
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