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guajiro [1.7K]
3 years ago
10

Identify the pair of angles.

Mathematics
1 answer:
patriot [66]3 years ago
8 0

Answer:

I believe the answer is Consecutive exterior

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Help 8th grade math
kondor19780726 [428]

you times each side by the number

5 0
3 years ago
H(x) = x^2+6 g(x) = 8x-5 <br><br> show that hg(x)=19 simplifies to 16x^2 - 20x + 3 = 0
Studentka2010 [4]

Answer:

h(x)=x²+6 and g(x)=8x-5

prove that hg(x)=19

Step-by-step explanation:

step 1: hog(x)=h[g(x)]

step 2: h(8x-5)

step 3: h(8x-5)= (8x-5)²+6

step 4: (8x-5)(8x-5)+6

step 5: 16x² +15x +6

6 0
3 years ago
4.) Find the quotient<br><br> 20 ÷ 1/4<br><br><br> A.) 5<br> B.) 40<br> C.) 10<br> D.) 80
Mazyrski [523]

1/4 of 20 is 5

A is the answer

7 0
3 years ago
A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs
LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

h=\frac{400}{\pi r^2}

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: h=\frac{400}{\pi r^2}

Therefore:

C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})

C(r)=0.12\pi r^2+\frac{24}{r}

C(r)=\frac{0.12\pi r^3+24}{r}

The minimum cost occurs when the derivative of the Cost =0.

C^{'}(r)=\frac{6\pi r^3-600}{25r^2}

6\pi r^3-600=0

6\pi r^3=600

\pi r^3=100

r^3=\frac{100}{\pi}

r^3=31.83

r=3.17 cm

Recall that:

h=\frac{400}{\pi r^2}

h=\frac{400}{\pi *3.17^2}

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0
3 years ago
What is 1/2(x+14) because i am having trouble solving it and no calculator has been able to help me also.
ivann1987 [24]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

\frac{1}{2}x+7

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Simplifying the equation...}}\\\\\frac{1}{2}(x+14)\\------------\\\rightarrow \frac{1}{2}*x = \frac{1}{2}x\\\\\rightarrow\frac{1}{2}*14=7\\\\\rightarrow     \frac{1}{2}(x+14)= \boxed{\frac{1}{2}x+7}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

7 0
3 years ago
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