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Irina18 [472]
3 years ago
5

2981/35=-11/7(8m+9/5

Mathematics
1 answer:
cricket20 [7]3 years ago
7 0

Answer:

Answer:

m=−7

Step-by-step explanation:

Let's solve your equation step-by-step.

2981

35

=

−11

7

(8m+

9

5

)

Step 1: Simplify both sides of the equation.

2981

35

=

−11

7

(8m+

9

5

)

2981

35

=(

−11

7

)(8m)+(

−11

7

)(

9

5

)(Distribute)

2981

35

=

−88

7

m+

−99

35

Step 2: Flip the equation.

−88

7

m+

−99

35

=

2981

35

Step 3: Add 99/35 to both sides.

−88

7

m+

−99

35

+

99

35

=

2981

35

+

99

35

−88

7

m=88

Step 4: Multiply both sides by 7/(-88).

(

7

−88

)*(

−88

7

m)=(

7

−88

)*(88)

m=−7

Answer:

m=−7

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4 years ago
(15 Points)
expeople1 [14]

ANSWER 1



Note that,


f(u)=tan^{-1}(u)


is the same as


f(u)=arctan(u)



We apply the product rule.


f(x)=x^2tan^{-1}(x)


So we keep the second function and differentiate the first,plus we keep the first function and differentiate the second.


f'(x)=(x^2)'tan^{-1}(x)+x^2(tan^{-1}(x))'



Recall that,

If

f(u)=tan^{-1}(u)



Then,

f'(u)=\frac{1}{1+u^2}} \times u'


This implies that,

f'(x)=2xtan^{-1}(x)+\frac{x^2}{x^2+1}



ANSWER 2


We apply the product rule and the chain rules of differentiation here.



f(x)=xsin^{-1}(1-x^2)




f'(x)=x'sin^{-1}(1-x^2)+x(sin^{-1}(1-x^2))'



Recall that,

If

f(u)=sin^{-1}(u)



Then,

f'(u)=\frac{1}{\sqrt{1-u^2}} \times u'



This implies that,


f'(x)=sin^{-1}(1-x^2)+x \times \frac{1}{\sqrt{1-(1-x^2)^2}}\times (-2x)


f'(x)=sin^{-1}(1-x^2)-\frac{2x^2}{\sqrt{1-(1-2x^2+x^4)}}


f'(x)=sin^{-1}(1-x^2)-\frac{2x^2}{\sqrt{1-1+2x^2-x^4}}



f'(x)=sin^{-1}(1-x^2)-\frac{2x^2}{\sqrt{2x^2-x^4}}





5 0
4 years ago
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