Question

Find the missing side of the triangle. leave your answer in simplest radical form

Answer 1

missing side is $x} = 10.15$ mi .

Step-by-step explanation:

Here we have the following info from the figure: A right angled triangle with following dimensions

$Perpendicular = x$

$base = \sqrt{122}$

$Hypotenuse = 15$

By Pythagoras Theorem :

$Hypotenuse^2 = Perpendicular^2 + base^2$

⇒ $Hypotenuse^2 = Perpendicular^2 + base^2$

⇒ $15^2 = x^2 + (\sqrt{122})^2$

⇒ $225 = x^2 + 122$

⇒ $x^2 = 225-122$

⇒ $x^2 = 103$

⇒ $(x^2)^\frac{1}{2} = (103)^\frac{1}{2}$

⇒ $x} = (103)^\frac{1}{2}$

⇒ $x} = 10.15$

Therefore, missing side is $x} = 10.15$ mi .