Question

3n^2=6-17n I need Vertex form please.

Answer 1

Answer:

3( n + $\frac{17}{6}$ )² - $\frac{361}{12}$ = 0

Step-by-step explanation:

3n² = 6 - 17n ⇔ 3n² + 17n - 6 = 0

3( n² + 2 × $\frac{17}{6}$ n + ( $\frac{17}{6}$ )² - ( $\frac{17}{6}$ )² - 2 ) = 0

3( n + $\frac{17}{6}$ )² - 3 × $\frac{289}{36}$ - 6 = 0

3( n + $\frac{17}{6}$ )² - $\frac{361}{12}$ = 0