There are 
ways of drawing a 4-card hand, where
is the so-called binomial coefficient.
There are 13 different card values, of which we want the hand to represent 4 values, so there are 
ways of meeting this requirement.
For each card value, there are 4 choices of suit, of which we only pick 1, so there are 
ways of picking a card of any given value. We draw 4 cards from the deck, so there are 
possible hands in which each card has a different value.
Then there are 
total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is
Answer:
1.rocky
Step-by-step explanation
1.we have the add the powers of x,not multiply.
Answer:
10
Step-by-step explanation:
Firstly, AM=x+8
or, A=x+8-M......eqn (i)
MB=6x-2
or, B=6x-2-M......eqn (ii)
Now,
from eqn (i) and (ii)
x+8-M=6x-2-M
or, 8+2=6x-x-M+M
or, 10=5x
or, 10÷5=x
therefore, x=2
Again,
MB=6x-2
=6×2-2
=12-2
=10
is it correct
please mark me as BRAINLIEST
If Stuart starts with -$54.19 then gains $70.82, you have to add the gained amount to the origin amount. Since the origin amount is negative, you can also subtract the origin amount from the gained amount to find the amount left at the end of the month.
Add 70.82 to -54.19
-54.19 + 70.82 = 16.63
<u>Alternative method:</u>
First, subtract 54.19 from 70.82.
70.82 - 54.19 = 16.63
Add 54.19 to -54.19, bringing you to 0.
-54.19 + 54.19 = 0
Now add the remaining 16.63.
0 + 16.63 = 16.63
<h2>Answer:</h2>
<u>Stuart will have </u><u>$16.63</u><u> at the end of this month.</u>
Not sure about the first one but the second one is option c (or -3). You just have to factor and find the solutions (so it would be -7 and 4 and then u just add them)
For question 39 the answer is c
