The force acting between two charged particles A and B is 5.2 x 105 newtons. Charges A and B are 2.4 x 102 meters apart. If the charge on particle A is 7.2 x 108 coulombs, what is the charge of particle B? (k 7 9.0 x 109 newton meters?/coulomb)
The fraction of the original amount remaining is closest to 1/128
<h3>Determination of the number of half-lives</h3>
- Half-life (t½) = 4 days
- Time (t) = 4 weeks = 4 × 7 = 28 days
- Number of half-lives (n) =?
n = t / t½
n = 28 / 4
n = 7
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 100 g
- Number of half-lives (n) = 7
- Amount remaining (N)=?
N = N₀ / 2ⁿ
N = 100 / 2⁷
N = 0.78125 g
<h3>How to determine the fraction remaining </h3>
- Original amount (N₀) = 100 g
- Amount remaining (N)= 0.78125 g
Fraction remaining = N / N₀
Fraction remaining = 0.78125 / 100
Fraction remaining = 1/128
Learn more about half life:
brainly.com/question/26374513
Answer is: 9623.85 kJ of heat is <span>transferred from iron ingot.
</span>m(Fe) = 24.7 kg · 1000 g/kg = 24700 g; mass of iron ingot.
C = 0.4494 J/g°C; t<span>he specific heat of iron
</span>ΔT = 880°C - 13°C; temperature <span>difference.</span>
ΔT = 867°C.
Q = m·C·ΔT.
Q = 24700 g · 0.4494 J/g°C ·867°C.
Q = 9623856.06 J ÷ 1000J/kJ.
Q = 9623.85 kJ.
Answer: Option (c) is the correct answer.
Explanation:
As we know that density the amount of mass present in per unit volume.
Mathematically, Density = 
So, it means that density is inversely proportional to volume. Hence, when there will be decrease in density of a substance then there will be increase in its volume. That is, expansion of substance will take place.
Also, boiling point of copper is 2,562 degree celsius but we are heating it up to a temperature of 95 degree celsius. This means that copper will remain in liquid state at this temperature.
Thus, we can conclude that a change which occurs in a sample of copper is that copper sample will expand.
