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Andrej [43]
2 years ago
6

The half-life of radon gas is approximately four days. Four weeks after the introduction of radon into a sealed room, the fracti

on of the original amount remaining is closest to
Chemistry
1 answer:
maksim [4K]2 years ago
7 0

The fraction of the original amount remaining is closest to 1/128

<h3>Determination of the number of half-lives</h3>
  • Half-life (t½) = 4 days
  • Time (t) = 4 weeks = 4 × 7 = 28 days
  • Number of half-lives (n) =?

n = t / t½

n = 28 / 4

n = 7

<h3>How to determine the amount remaining </h3>
  • Original amount (N₀) = 100 g
  • Number of half-lives (n) = 7
  • Amount remaining (N)=?

N = N₀ / 2ⁿ

N = 100 / 2⁷

N = 0.78125 g

<h3>How to determine the fraction remaining </h3>
  • Original amount (N₀) = 100 g
  • Amount remaining (N)= 0.78125 g
  • Fraction remaining =?

Fraction remaining = N / N₀

Fraction remaining = 0.78125 / 100

Fraction remaining = 1/128

Learn more about half life:

brainly.com/question/26374513

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If 38.5 grams of potassium react with excess oxygen gas, how many grams of potassium oxide can be produced? 4K + O2 yields 2K2O
Lera25 [3.4K]

Answer:

46.40 g.

Explanation:

  • It is a stichiometric problem.
  • The balanced equation of the reaction: 4K + O₂ → 2K₂O.
  • It is clear that 4.0 moles of K reacts with 1.0 mole of oxygen produces 2.0 moles of K₂O.
  • We should convert the mass of K (38.5 g) into moles using the relation:

<em>n = mass / molar mass,</em>

n = (38.5 g) / (39.098 g/mol) = 0.985 mole.

<em>Using cross multiplication:</em>

4.0 moles of K produces → 2.0 moles of K₂O, from the stichiometry.

0.985 mole of K produces → ??? moles of K₂O.

∴ The number of moles of K₂O produced = (0.985 mole) (2.0 mole) / (4.0 mole) = 0.4925 mole ≅ 0.5 mole.

  • Now, we can get the mass of K₂O:

∴ mass = n x molar mass = (0.5 mole) (94.2 g/mol) = 46.40 g.

6 0
3 years ago
What else is produced during the combustion of butane, C4H10?
denpristay [2]

Another product: CO₂

<h3>Further explanation</h3>

Given

Reaction

2C₄H₁₀ + 13O₂⇒ 8__+ 10H₂O

Required

product compound

Solution

In the combustion of hydrocarbons there can be 2 kinds of products

If there is excess Oxygen, you will get Carbon dioxide(CO₂) and water in the product

If Oxygen is low, you'll get Carbon monoxide(CO) and water

Or in other ways, we can use the principle of the law of conservation of mass which is also related to the number of atoms in the reactants and in the products

if we look at the reaction above, there are C atoms on the left (reactants), so that in the product there will also be C atoms with the same number of C atoms on the left

2C₄H₁₀ + 13O₂⇒ 8CO₂+ 10H₂O

5 0
2 years ago
Read 2 more answers
Which out of two has stronger forces of attraction sugar or water very sort answer​
Marina CMI [18]

Sugar. It is solid and its atoms have less kinetic energy to overcome the bonding force. So, the bonding force is stronger than water, which is liquid and has more kinetic energy to overcome the bonding force of atoms. So, water has less strong force of attraction. Hence, sugar has stronger forces of attraction.

8 0
3 years ago
!HELP ASAP!!!
Snowcat [4.5K]

Answer:

Covalent Bonds

Explanation:

INTERmolecular forces are those that exist between molecules, so you can think of it liek international things taking place between countries. As you are aware, dipoles exist across an entire molecule, so for 2 dipoles to interact, there needs to be 2 molecules. Van der Waals forces also take place between  molecules when there is an uneven distribution of electrons across a molecule, causing a temporary weak dipole. Hydrogen bonding is similar to dipole-dipole forces, but only happen when there is a hydrogen interacting with an atom on another molecule that has a lone pair of electrons.

Covalent bonds, however, are INTRAmolecular, meaning they are present within a molecule. Covalent bonds are the bonds that exist when two atoms, within the same molecule, share electrons so both can have a stable electron configuration.

Hope I helped! xx

6 0
3 years ago
Read 2 more answers
Which conversion factor is needed to solve the following problem?
USPshnik [31]
Molar Volume is required to solve this problem. As we know that "1 mole of any gas at standard temperature and pressure occupies 22.4 L of volume". SO using this concept, we can calculate the volume of ammonia formed by reacting 54.1 L of Hydrogen gas as follow,

3 0
3 years ago
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