Answer:
50 mph
Explanation:
To figure out how many miles per hour this car is going, we divide the distance traveled by the time it took.
200 ÷ 4 = 50
Answer:
The reaction proceeds through the SN-1 mechanism.
Explanation:
Based on the question given, the ratio of elimination to substitution is the same (26% elimination) for 2−bromo−2−methylbutane and 2−iodo−2−methylbutane in 80% ethanol/20% water at 25°C.
The formation of the same ratio of products from different starting materials is only possible when both reactions are proceeding with thesame intermediates.
In SN-1 and E-1 mechanism, reaction proceeds via a carbocation mechanism, whereas in the case of SN-2 mechanism, the nucleophile attacks the back side of the leaving group.
In the case of E-2 mechanism, both the beta and halide leaves at the same time to form an alkene.
Hence, the substitution reaction given in the question proceeds through the carbocation intermediate. This implies that the reaction proceeds through the SN-1 mechanism.
The path of energy flow from the sun to the humpback whale is as follows:
- Sun---> Plankton ---> Small fishes ---> Humpback whale.
<h3>What is energy?</h3>
Energy is the ability to do work.
The primary source of energy on the earth is the sun.
The energy from the sun is used by producers to produce food on which other organisms depend on.
The energy from the sun gets to the humpback whale through producers such as plankton.
The path of energy flow from the sun to the humpback whale is as follows:
- Sun---> Plankton ---> Small fishes ---> Humpback whale.
Learn more about energy flow at: brainly.com/question/21786633
<span>Using proportions,
if x is the unknown volume we have:
1.84 / 1 = 42.5 / x </span>
<span>
Multiply both sides above by x:
1.84*x / 1 = 42.5
1.84*x = 42.5
Divide both sides by 1.84:
x = 42.5 / 1.84</span>
<span>X = 23.10 mL</span>
The answer is the coefficient is "1".
C₅H₁₀, now you see that there is no number with this and when there is no number or digit, it means the coefficient is one.
we use the coefficients to balance the equation of the reaction in such a way that number of the atoms of the elements in the reactants are equal to the number of atoms of different elements in the product, so that both sides are equal and balanced.