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IrinaVladis [17]
3 years ago
11

Higher Order Thinking.

Mathematics
1 answer:
defon3 years ago
7 0
Pat has 4 more cards than Frank. Hope that helps! :) 
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Bonita evaluated 56 × 123 and got an answer of 73. How can you tell that her answer is wrong?
bixtya [17]
Show the equation for example 56x123=6888
8 0
3 years ago
Plz help i dont know how to do this
liubo4ka [24]

Answer:

Step-by-step explanation:

g to the power of 8 *h hope this helped

nh to the power of 8

8 0
3 years ago
A circle has a diameter of 4 meters. What is the best approximation of its area? Use 3.14 to approximate for π . 6.28 m² 12.56 m
hram777 [196]
 i would go with 12.56

7 0
4 years ago
Read 2 more answers
Suppose you roll a six-sided 50 times and calculate the mean roll, x .
Vitek1552 [10]

Answer:

0.07

a. the distribution will be a normal distribution.

c. we would suspicious ins there is a 2 % chance of getting the required value.

Step-by-step explanation:

Let the number of times, t be = 50

Assuming that the die is fair

standard deviation = 1.71

mean = 3.5

suppose we want tp find the probability of a 2 showing. The solution becomes:

probability = \frac{2}{6}  = \frac{1}{3}

c. the  mean of rolls will be 0.07

8 0
4 years ago
A pride of lions is growing at a rate of 0.5% per year, compounded continuously. If the growth rate continues, how many years wi
guajiro [1.7K]

Answer:

Step-by-step explanation:

The general formula for continuous exponential growth is A=A0•ert, where A0 is the initial amount, t is the elapsed time, and r is the rate of growth or decay. For this problem, r=0.005, so the formula is A=A0•e0.005t.

Since we want to know how long it takes of the amount to be 275% of the original amount, we can state that A=2.75A0. Substituting that into our formula gives us 2.75A0=A0•e0.005t. Dividing by A0 yields 2.75=e0.005t.

At this point we need to take the natural logarithm of both sides:

ln(2.75)=ln(e0005t)

ln(2.75)=0.005t

t=ln(2.75)/0.005, which is approximately equal to 202.3

We round up to 203 years.

6 0
4 years ago
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