Answer:
Step-by-step explanation:
Let the base camp is point A and boats' locations after two hours are points B and C.
By connecting the three points together we get a triangle ABC with sides:
- AB = 50*2 = 100 km
- AC = 70*2 = 140 km
The angle between AB and AC is:
- 60 + 50 = 110 degrees (opposite directions from south)
We are looking for the distance BC, which can be found by using the law of cosines:
- BC² = AB² + AC² - 2AB*AC*cos ∠BAC
- BC² = 100² + 140² - 2*100*140*cos 110°
- BC² = 39176.56 (rounded)
- BC = √39176.56 = 197.93 km (rounded)
The distance between the boats is 197.93 km.
Answer:
D. 14
Step-by-step explanation:
a^2+b^2=square of c
a^2+x^2=50
Answer:
See attached graph
Step-by-step explanation:
The equation is y-3=(x + 6)
Write the equation in a slope intercept form, then graph the equation on a graph tool to see the points that line on the line.
Alternatively , using the coordinates in the answer choices given, input them in the equation of the graph and select the answer choice that has all its coordinates true to the equation.
y-3 = x+6 -----can be written as : y= x+9
Graph y= x+9 to see the graph and the points that are on the line as attached.
Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(11,4)(10,5)
d = sqrt (10 - 11)^2 + (5 - 4)^2
d = sqrt (-1^2) + (1^2)
d = sqrt (1 + 1)
d = sqrt 2
d = 1.41 <===
Answer:
B
Step-by-step explanation:
First simplify the first term to get
10y^4
then multiply 10y^4 by 4 square root 6y^3
40y would be all you needed to get answer
