Six times a number is greater than 20 more than that number. What are the possible values of that number?

Mathematics

1 answer:

Ghella [55]2 years ago

8 0

Answer:

Im not completely sure but it could be 120 because if it's 20 time more of value than 6 than you could do like 6x20 im not completely sure tho.

Step-by-step explanation:

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I have no idea!! Please help!!!

Ber [7]

The area of a traingle is $\frac{1}{2}bh$
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²= $\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}$
a= $\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}$

A= $\frac{1}{2}bh$
A= $\frac{1}{2}a*a$
A= $\frac{1}{2}$ × $\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}$ × $\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}$
A= $\frac{1}{2}$ × $\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}$
A= $\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}$