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-Dominant- [34]
4 years ago
12

A recipe calls for 2 3/4 cups of milk. if the recipe is tripled, how much milk is needed?

Mathematics
1 answer:
SSSSS [86.1K]4 years ago
5 0
To be tripled means to be multiplied by 3. So multiply 2 3/4 by 3
2 3/4*3=8 1/4
Therefore the amount of milk needed is 8 1/4 cup
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Taltson Lake is in the Canadian Northwest Territories. This lake has many Northern Pike. The following data was obtained by two
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The sample correlation coefficient r is equal to 0.9962

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3 years ago
Choose 3 values that would make thi inequalitie true 28+x&gt;42
Y_Kistochka [10]

9514 1404 393

Answer:

  14.01, 493, 87

Step-by-step explanation:

Subtracting 28 from both sides tells you the range of values you need to be looking at.

  28 + x > 42

  x > 14

Any values more than 14 will make the inequality true. Three of them are ...

  14.01, 493, 87

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3 years ago
Katie put a $980 item on layaway by making a down payment of 14% of the purchase price. How much does she have left to pay after
Tanzania [10]

Answer:

$842.8

Step-by-step explanation:

It says that Katie already paid the 14% of the item as a down payment, so she needs to pay the remaining 86% of the item.

To get that, it is:

$980 x 86% = $842.8

8 0
4 years ago
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
For a normal distribution, is it likely that a data value selected at random is more than 2 standard deviations above the mean?
makkiz [27]

Answer:

P(X>\mu + 2\sigma)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

Using the z score formula we want this probability:

P(Z>2)

And using the complement rule we got:

P(Z>2) = 1-P(Z

And that correspond to only 0.023*100= 2.3%, so is not frequently and the most appropiate answer for this case would be:

No. This event happens only 2.5% of the time

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interst of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

Where \mu the mean and \sigma  the deviation

We are interested on this probability

P(X>\mu + 2\sigma)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

Using the z score formula we want this probability:

P(Z>2)

And using the complement rule we got:

P(Z>2) = 1-P(Z

And that correspond to only 0.023*100= 2.3%, so is not frequently and the most appropiate answer for this case would be:

No. This event happens only 2.5% of the time

8 0
4 years ago
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