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2 years ago

14

See the picture please!!

1 answer:

jeka57 [31]2 years ago

7 0

Answer:

the first one its true

y of A greater than the y of B

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What is the answer to 0.657/9 ?

Artemon [7]

Answer:

the answer is 0.073

Step-by-step explanation:

0.657/9= 0.073

8 0

3 years ago

Find an m > 0 such that the the equation x^4−(3m+2)x^2+m^2=0 has four real solutions that form an arithmetic sequence.

Aleonysh [2.5K]

Answer:

The value of m is 6.

Step-by-step explanation:

Here, the given equation,

$x^4-(3m+2)x^2+m^2=0$

$x^4+0x^3-(3m+2)x^2+0x+m^2=0$

Let the roots of the equation are a-3b, a-b, a+b and a + 3b, ( they must be form an AP )

Thus, we can write,

$a-3b+a-b+a+b+a+3b=\frac{\text{coefficient of }x^3}{\text{coefficient of }x^4}$

$=\frac{0}{1}=0$

$\implies a=0----(1)$

$(-3b)(-b)+(-b)(b)+(b)(3b)+(3b)(-3b)+(-b)(3b)+(-3b)(b)=\frac{\text{coefficient of }x^2}{\text{coefficient of }x^4}}$

$=\frac{-3m-2}{1}$

$3b^2-b^2+3b^2-9b^2-3b^2-3b^2=-3m-2$

$-10b^2=-3m-2$

$\implies b^2=\frac{3m+2}{10}-----(2)$

$(-3b)(-b)(b)(3b)=\frac{\text{Constant term}}{\text{coefficient of}x^4}= m^2$

$9b^4=m^2$

$9(\frac{3m+2}{10})^2=m^2$

$9(\frac{9m^2+4+12m}{100})=m^2$

$81m^2+36+108m=100m^2$

$-19m^2+108m+36=0$

$19m^2-108m-36=0$

$19m^2-114m+6m-36=0$

$19m(m-6)+6(m-6)=0$

$(19m+6)(m-6)=0$

$\implies m=-\frac{6}{19}\text{ or }m=6$

But m > 0,

Hence, the value of m is 6.

4 0

3 years ago

Which number below is a perfect square? 100 90 50 75

Umnica [9.8K]

100

ggbnjj mj ddcnmikiyewazxbnoorr

4 0

2 years ago

HELP PLS<br> idk how to do this<br> It's called Project: Let's get cooking!

Anastaziya [24]

Answer: What exactly do you need help with

4 0

3 years ago

Which function has an average rate of change of -4 over the interval [-2,2]?

kolbaska11 [484]

Only p(x) has an average rate of change of -4 over [-2, 2].

Find the average rate of change of each given function over the interval [-2, 2]]:

The average rate of change of m(x) over [-2, 2]:

<h3>What is the average rate?</h3>

The average rate of change = $\frac{m(b)-m(a)}{b-a}$

Where, a = -2, m(a) = -12

b = 2, m(b) = 4

Plug the values into the equation

The average rate of change

$=\frac{4-(-12)}{2-(-2)} =\frac{16}{4}$

The average rate of change = 4

The average rate of change of n(x) over [-2, 2]:

The average rate of change = $\frac{n(b)-n(a)}{b-a}$

Where, a = -2, n(a) = -6

b = 2, n(b) = 6

Plug the values into the equation

The average rate of change

$=\frac{6-(-6)}{2-(-2)} \\=\frac{12}{4}$

The average rate of change = 3

The average rate of change of q(x) over [-2, 2]:

The average rate of change = $\frac{q(b)-q(a)}{b-a}$

Where, a = -2, q(a) = -4

b = 2, q(b) = -12

Plug the values into the

The average rate of change = $\frac{-4-12}{2-(-2)}$

= $\frac{-16}{4}$

The average rate of change = -2

The average rate of change of p(x) over [-2, 2]:

The average rate of change = $\frac{p(b)-p(a)}{b-a}$

Where, a = -2, p(a) = 12

b = 2, p(b) = -4

Plug the values into the equation

The average rate of change = $\frac{-4-12}{2-(-2)}$

$=\frac{-16}{4}$

The average rate of change = -4

The answer is D.

Only p(x) has an average rate of change of -4 over [-2, 2].

To learn more about the average rate of visit:

brainly.com/question/8728504

#SPJ1

8 0

1 year ago