You are laying in a field flying a kite and have let out 60 meters of string. The kites angle of elevation with the ground is 40
degrees, if the string is stretched straight, how high is the kite above the ground
2 answers:
Answer: 38.56 m
Step-by-step explanation:
Hi, since the situation forms a right triangle (see attachment) we have to apply the next trigonometric function.
sin α = opposite side / hypotenuse
Where α is the angle of elevation of the kite to the ground, the hypotenuse is the longest side of the triangle (in this case is the length of the string), and the opposite side (c) is the length of the kite above the ground
Replacing with the values given:
sin 40 = c/60
Solving for c
sin40 (60) =c
c= 38.56 m
Feel free to ask for more if needed or if you did not understand something.
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9514 1404 393
Answer:
- e ≈ 9.608
- D ≈ 46.5°
- F ≈ 38.5°
Step-by-step explanation:
The only given angle is between the two given sides, so the Law of Cosines must be used to find the side opposite the angle. It tells you ...
e² = d²+f² -2df·cos(E)
e² = 7² +6² -2·7·6·cos(95°) ≈ 92.321082
e ≈ 9.608
The remaining angles can be found from the law of sines.
sin(D)/d = sin(E)/e
D = arcsin(d/e·sin(E)) ≈ arcsin(7/9.608·sin(95°)) ≈ 46.5°
F = 180° -95° -46.5° = 38.5°
