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Minchanka [31]
3 years ago
9

Select the correct answer. Which number is located to the right of on the horizontal number line? A. -1 1/3 B. -2 1/3 C. -2 2/3

D. -3 1/3
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
7 0

Answer:

A. -1 1/3

Step-by-step explanation:

I am assuming you want to find the number that is farthest to the right of all 4 possible choices. In that case, the bigger the negative number, the farther left it is on the number line. The smaller the negative number, the farther right it is on the number line.

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A) 2.5x + 1.25 &lt; 3.75 <br>b)5.12 2.4x + 0.3<br>help!!!<br><br>​
Sauron [17]

Answer:

a) 1

b)I would like to help u but i don't understand the question I think something is missing there plus sign or minus sign sry

Step-by-step explanation:

2.5x + 1.25 < 3.75

2.5x < 3.75 - 1.25

2.5x < 2.5

\frac{2.5x}{2.5}  =  \frac{2.5}{2.5}

x = 1

I hope u like it ‍❤️‍‍❤️‍

For any question comment me

Really sorry for the second question

4 0
4 years ago
Write a equation of a hyperbola given the foci and the asymptotes
professor190 [17]

Solution:

The standard equation of a hyperbola is expressed as

\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}

The asymptote of n hyperbola is expressed as

y=\pm\frac{a}{b}(x-h)+k

Given that the asymptotes are

y=\frac{3}{4}x\text{ and y=-}\frac{3}{4}x

This implies that

a=3,\text{ and b=4}

To evaluate the value of h and k,

undefined

3 0
1 year ago
Florence works in the shipping department of a toy factory that makes radio-controlled helicopters. Small helicopters weigh 3 ki
Damm [24]

Answer:

50 kg

Step-by-step explanation:

Given that:

SMALL HELICOPTERS:

Weight of small helicopters = 3kg

Weight of shipping container = 20kg

LARGE HELICOPTERS:

Weight of large helicopters = 4kg

Weight of shipping container = 10kg

Number of helicopters each shipping container can hold = s ; all of the packed containers will have the same shipping weight

Shipping weight :

(Weight per helicopter * number of helicopter) + weight of shipping container

Shipping weight of Small helicopters :

(3kg * s) + 20

Shipping weight Large helicopters :

(4kg * S) + 10

Shipping weight of Small helicopters = shipping weight of large helicopters

3s + 20 = 4s + 10

20 - 10 = 4s - 3s

10 = s

Hence, member of shipped helicopters = 10

Total shipping weight :

(4 * S) + 10

(4*10) + 10

40 + 10 = 50kg

4 0
3 years ago
The ratio of pencils to erasers is 4:1. if there are 20 pencils, how many erasers are there?
serious [3.7K]
5 Erasers, 4:1 is equal to 20:5, if you just multiply both numbers by 5
7 0
4 years ago
Read 2 more answers
Can someone pls pls PLS, help me out? ASAP!! (Geometry)<br> “Complete the proof”
Maru [420]

1) \overline{AB} \perp \overline{BD}, \overline{AB} \cong \overline{DB}, \overline{AC} \cong \overline{DE} (given)

2) \angle ABD is a right angle (perpendicular lines form right angles)

3) \triangle ABD and \triangle DEB are right triangles (a triangle with a right angle is a right angle)

4) \triangle ABD \cong \triangle DEB (HL)

5) \angle ACB \cong \angle DEB (CPCTC)

8 0
2 years ago
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