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Romashka-Z-Leto [24]

3 years ago

11

A step-down transformer has 1027 turns on the side which draws from a high voltage line (2201 V). How many turns does it need on

the low voltage side to supply a house with current at 120 V?

1 answer:

Pepsi [2]3 years ago

3 0

Answer:

I think it would be 56.

Explanation:

# of turns/ 1027 = 120/2201

# of turns = (120*1027)/2201

# of turns = 55.9927

Basically ≈ 56?

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Critical Thinking

Sophie [7]

OK.

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The airplane is maybe 7 miles up, passing over the ground at nearly
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3 years ago

What do we call the study of the science of movement

nalin [4]

We call it: Biomechanics

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4 years ago

Consider two planets of mass m and 2m,

Rzqust [24]

Answer:

Part a)

$\frac{F_1}{F_2} = 10.125$

Part b)

$\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12$

Part c)

$\frac{T_1}{T_2} = 9.54$

Explanation:

Part a)

As we know that the gravitational force is given as

$F = \frac{GMm}{r^2}$

so we will have to find the ratio of force on two planets due to star

so here we have

$\frac{F_1}{F_2} = \frac{m_1r_2^2}{m_2r_1^2}$

$\frac{F_1}{F_2} = \frac{m (4.5r)^2}{(2m) r}$

$\frac{F_1}{F_2} = 10.125$

Part b)

Orbital speed is given as

$v = \sqrt{\frac{GM}{r}}$

so the ratio of two orbital speed is given as

$\frac{v_1}{v_2} = \frac{r_2}{r_1}$

$\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12$

Part c)

Time period is given as

$T = 2\pi\sqrt{\frac{r^3}{GM}}$

so the ratio of two time period is given as

$\frac{T_1}{T_2} = \sqrt{\frac{r_1^3}{r_2^3}}$

$\frac{T_1}{T_2} = \sqrt{\frac{4.5r^3}{r^3}}$

$\frac{T_1}{T_2} = 9.54$

8 0

3 years ago

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Consider a 40,000 km steel pipe in the shape of a ring that fits snuggly all around the circumference of the Earth. We are heati

Tatiana [17]

Answer:

The Height is H = 70.02 m

Explanation:

We are given that the

Initial length is = $40000\ Km$ = $40,000 *10^{3} m$

from what we are told in the question the circumference of the circle is = $40,000 Km$

This means that the Radius would be :

Let C denote the circumference

So

$C = 2 \pi r$

=> $r = \frac{C}{2 \pi}$

$r = \frac{40,000}{2 \pi } = \frac{40,000*10^{3}}{2 *3.142} = 6.365*10^6 m$

We are told that 1-meter bar of steel that increases its temperature by 1 degree C will expand $11*10^{-6}$ meters

Hence

The final length would be

$40000*10^3 *(T + \alpha )$

Where T is the change in temperature $\alpha$ is the Coefficient of linear expansion for steel

let $L_{final}$ denote the final length

So

$L_{final} =40000*10^{6} *[1+ 11*10^{-6}]$

$= 40000440 \ m$

Now the Height is mathematically represented as

$Height(H) \ = \frac{change \ in \ radius \ }{2 \pi}$

$= \frac{(40000440-40000*10^3)}{2*3.142}$

$= 70.02m$

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4 years ago

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alexandr1967 [171]

I think d because the water can make the humidity go down and make the air cool

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3 years ago

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