Describing motion from each frame of reference:
Since observer A is on one of the train's cars, he will find that he is at rest with respect to the train even when it is pulling away because, he is also moving with respect to the train.
Observer B on the stationary platform will observe that the train is pulling away from the station towards the right of the platform. as is described
Observer C will notice that the train is approaching him in the opposite direction at a speed which is the sum of the speeds at which both the train are traveling
If the conductor applies brakes on the train, since the platform is a stationary frame of reference. The motion will be observed as a simple decelerationg. he will observe that the force due to the brakes will cause the velocity of the train with respect to the train to decrease
Universal law of gravitation effects all objects alike . There will be a constant force of gravity acting on the train that will keep the train on its tracks. The tracks in turn exert a reaction force on the train. There will not be any affect on the train's motion as such( assuming that the train is moving along the tracks and gravitational force is exactly perpendicular)
Answer:
The impulse is 1.89 Ns and final velocity of the golf 4.17 
Explanation:
Given:
Average force 
N
Contact time 
sec
Mass of golf ball 
kg
(a)
Impulse is given by,
Ns
(b)
For finding the final velocity,
Therefore, the impulse is 1.89 Ns and final velocity of the golf 4.17
Answer:
The correct answer is a. Both are the same
Explanation:
For this calculation we must use the gravitational attraction equation
F = G m M / r²
Where M will use the mass of the Earth, m the mass of the girl and r is the distance of the girl to the center of the earth that we consider spherical
To better visualize things, let's repair the equation a little
F = m (G M / r²)
The amount in parentheses called acceleration of gravity, entered the force called peos
g = G M / r²
F = W
W = m g
When analyzing this equation we see that the variation in the weight of the girl depends on the distance, which is the radius of the earth plus the height where the girl is
r = Re + h
Re = 6.37 10⁶ m
r² = (Re + h)²
r² = Re² (1 + h / Re)²
Let's replace
W = m (GM / Re²) (1+ h / Re)⁻²
W = m g (1+ h / Re)⁻²
This is the exact expression for weight change with height, but let's look at its values for some reasonable heights h = 6300 m (very high mountain)
h / Re = 10
⁻³
(1+ h / Re)⁻² = 0.999⁻²
Therefore, the negligible weight reduction, therefore, for practical purposes the weight does not change with the height of the mountain on Earth
The correct answer is a
Answer:
281.6 K
Explanation:
The speed of sound in an ideal gas is given by c = √(γKT/m).
From the question speed of sound in Ne, c₁ = 2c₂ speed of sound in Kr
c₁ = √(γKT₁/m₁) and c₂ = √(γKT₂/m₂)
So √(γKT₁/m₁) = 2√(γKT₂/m₂) where T₁, m₁ and T₂, m₂ are the temperatures and atomic masses of Neon and Krypton respectively.
So, √(T₁/m₁) = 2√(T₂/m₂)
(T₁/m₁) = 4(T₂/m₂) (squaring both sides)
T₁ = 4(T₂m₁/m₂)
Given that m₁ = 20.2 u , m₂ = 83.8 u, T₂ = 292 K
T₁ = 4(292 × 20.2/83.8) K = 23593.6/83.8 = 281.55 K ≅ 281.6 K
The pressure exerted by a fluid solely relies on the depth or height of the fluid, its density, and the gravitational constant. These three are related in the equation:
Pressure = density x g x height
In the problem, point A is within the block inside the tank. The water above the block is assumed to be 0.6 meters. This gives a point A pressure of:
P = 1000 kg/m^3 * 9.81 m/s^2 * 0.6 m = 5,886 Pa or 5.88KPa
