Answer:
Removing O₂, means removing one of the reactants and the system would counteract this effect by producing more O₂, thereby shifting the equilibrium position to the left and favouring the backward reaction.
Explanation:
The principle that explains how changes in temperature, Concentration and Pressure of reactants or products of a reaction at equilibrium affect the equilibrium position of the reaction is the Le Chatelier's principle.
The Principle explains that a system/process if a system/process which is at equilibrium is disturbed/perturbed/constrained by one or more changes (in concentration, pressure or temperature), the system would shift the equilibrium position to counteract the effects of this change.
Removing O₂, means removing one of the reactants (changing its concentration) and the system would counteract this effect by producing more O₂, thereby shifting the equilibrium position to the left and favouring the backward reaction.
Nearly all life on Earth gets its energy from the sun, and the sun gets its energy through the process of nuclear fusion, which is why these type of energy is important to life on Earth.
Answer:
a) a space in an atom where an electron is most likely to be found
Explanation:
Atomic orbital is the mathematical function which describes wave-like behavior of the electrons present in the atom.
It is used to calculate probability of finding the electron of the atom in any region around nucleus of the atom. Atomic orbital is the physical region or a three dimensional space where the probability of finding the electron is more than 90% which also means that the space where an electron is most likely to be found. They are boundless space and have definite energy.
Option A best describes atomic orbital.
Pentane is the correct answer the prefix pent means 5 so 5 hydrogens
Answer:
a) 24.7 mol
b) 790 g
Explanation:
Step 1: Given data
- Volume of the chamber (V): 200. L
- Room temperature (T): 23 °C
- Pressure of the gas (P): 3.00 atm
Step 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 23°C + 273.15 = 296 K
Step 3: Calculate the moles (n) of oxygen
We will use the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol
Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen
The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.
m = n × M
m = 24.7 mol × 32.00 g/mol = 790 g
