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Alchen [17]
2 years ago
15

• How did your experimental absolute zero value compare to the accepted value?

Chemistry
1 answer:
Murrr4er [49]2 years ago
5 0

The experimental absolute zero value is less when compared to the accepted value of absolute zero.

<h3>What is absolute zero?</h3>

Absolute zero is defined as the temperature in which the lowest energy possible is attained in a thermodynamic system.

Absolute zero temperature has an accepted values of 0 Kelvin or -273.15 degrees Celsius.

At absolute zero, it is assumed that the volume of an ideal gas becomes zero. However, it has not been possible to cool any gas to absolute zero.

Based on the graph of temperature against volume of gases, the experimental absolute zero extrapolated from the graph where volume of the gases becomes zero is -285 degrees Celsius.

Therefore, the experimental absolute zero value is less when compared to the accepted value.

Learn more about absolute zero at: brainly.com/question/1191114

#SPJ1

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The density of a metal is 9.80 g/mL. What is the mass of a sample of metal when dropped in 28.9 mL of water, the volume increase
yan [13]

The correct answer is 2.70 × 10² g or 270 g.  

It is given, that the density of a metal is 9.80 g/ml.  

Let the mass of a sample of metal be x.  

The sample of metal is dropped in 28.9 ml of water, due to which the volume of the water increases to 56.4 ml.  

In order to calculate the mass of a metal, there is a need to use the formula, mass = density * volume

Mass = (9.80 g/ml) (56.4 ml - 28.9 ml)

= (9.80 g/ml) (27.5 ml)

= 2.70 × 10² g or 270 g


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