Answer:
C. 500 cm' of 1.0 mol dmº magnesium sulphate solution.
Explanation:
Let us look at each of the solutions individually;
CaCl2 has three particles
K2SO4 has three particles
MgSO4 has two particles
C2H5OH has only one particle
The number of moles of moles in 250 cm of 2.0 mol dm-3 potassium chloride is 250/1000 * 2 = 0.5 moles having two particles
Also; number of moles in 500 cm' of 1.0 mol dm-3 magnesium sulphate solution= 500/1000 * 1 = 0.5 moles having two particles
Answer:
V = 210.5 mL
Explanation:
∴ C1 = 0.95
∴ C2 = 0.40
∴ V2 = 0.500 L
⇒ V1 = ((0.50)(0.40))/(0.95)
⇒ V1 = 0.2105 L
Answer:
K = K1×K2 = [CO2] [H2]⁴ / [H₂O]² [CH4]
Explanation:
Based on the reactions:
CH2 (g) + H2O(g) ⇄ CO (g) + 3H2 (g) K1
CO (g) + H2O (g) ⇄ CO2 (g)+H2(g) K2
The sum of both reactions is:
CH4 (g)+2H2O (g) ⇄ CO2(g)+4H2(g) And K of the reaction is: K = K1×K2
K is defined as the ratio between concentrations of products and reactans. Each compound must be elevated to its coefficient in the reaction. That is:
<h3>K = K1×K2 = [CO2] [H2]⁴ / [H₂O]² [CH4]</h3>
Answer : The heat required is, 1904 calories.
Explanation :
The process involved in this problem are :
The expression used will be:
![\Delta H=m\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]](https://tex.z-dn.net/?f=%5CDelta%20H%3Dm%5Ctimes%20%5CDelta%20H_%7Bfusion%7D%2B%5Bm%5Ctimes%20c_%7Bp%2Cl%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D)
where,
m = mass of ice = 17 g
= specific heat of liquid water = 
= enthalpy change for fusion = 
Now put all the given values in the above expression, we get:
![\Delta H=17g\times 80.0cal/g+[17g\times 1cal/g^oC\times (32.0-0)^oC]](https://tex.z-dn.net/?f=%5CDelta%20H%3D17g%5Ctimes%2080.0cal%2Fg%2B%5B17g%5Ctimes%201cal%2Fg%5EoC%5Ctimes%20%2832.0-0%29%5EoC%5D)
Therefore, the heat required is, 1904 calories.
