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Mumz [18]
4 years ago
8

Calculate the percent covalent character of a chemical bond between oxygen and beryllium.

Chemistry
1 answer:
dezoksy [38]4 years ago
8 0

Beryllium Oxide has a molecular formula Be-O

% covalent character in Be-O = 100 - % ionic character in Be-O

Now,

% ionic character = {1 - exp[(-0.25)(E(Be)-E(O))²]}*100

where,

E(Be) and E(O) are the electronegativity values of Be and O

Based on the Paulings scale:-

E(Be) = 1.57

E(O) = 3.44

% ionic = {1 - exp[(-0.25)(1.57-3.44)²]}*100 = 58.28%

Therefore, % covalent = 100 -58.28 = 41.72%

Ans: b) 41 percent

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Write a food chain in which the hawk is a secondary consumer:​
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On combustion, 1.0 L of a gaseous compound of hydrogen, carbon, and sulfur gives 2.0 L of CO2, 3.0 L of H2O vapor, and 1.0 L of
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Answer:

The empirical formula of the organic compound is  = C_2H_6S_1

Explanation:

At STP, 1 mole of gas occupies 22.4 L of volume.

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n\times 22.4L=2.0L

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Moles of H_2O gas at STP occupying 3.0 L = n'

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Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of SO_2 gas at STP occupying 1.0 L = n''

n''\times 22.4L=1.0L

n''=\frac{1.0 L}{22.4 L}=0.04464 mol

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

Moles of carbon , hydrogen and sulfur constituent of that organic compound .

Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

For empirical; formula divide the least number of moles from all the moles of elements.

carbon = \frac{0.08920 mol}{0.04464 mol}=2

Hydrogen =  \frac{0.2678 mol}{0.04464 mol}=6

Sulfur = \frac{0.04464 mol}{0.04464 mol}=1

The empirical formula of the organic compound is  = C_2H_6S_1

3 0
3 years ago
Why do we observe national day​
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The concentration of dye in Solution A is 26.609 M. You have 13 mL of water at your disposal to make the dilutions. The solution
exis [7]

Answer:

6,613 M

Explanation:

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