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Shtirlitz [24]
3 years ago
12

You have 15 pennies in your pocket. Of those pennies, 4 are Canadian. Suppose you pick a penny out of your pocket at random. Fin

d P(not Canadian).
Mathematics
1 answer:
vlada-n [284]3 years ago
6 0

Answer:

11/15

Step-by-step explanation:

If 4 out of 15 are Canadian, the ratio of the probability of picking a Canadian is 4/15.  That means that the probability of NOT picking a Canadian is the complement of 4/15 which is 11/15.  Therefore, the probability of not picking a Canadian is the same thing as the probability of picking an American penny which is 11/15.

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If something is $380, then the sellers mark up the price by 84%, what is the final sale price??
nadya68 [22]
699.2 is correct answer
4 0
3 years ago
Evaluate this expression what is <br> b=-6 and c=7.c-7b
VLD [36.1K]

Answer:

49

Step-by-step explanation:

substitute b = - 6 and c = 7 into the expression and evaluate

c - 7b = 7 - (7 × - 6) = 7 - (- 42) = 7 + 42 = 49


7 0
3 years ago
Find the 50th term of 0,3,6,9
damaskus [11]

Answer:

150

Step-by-step explanation:

3×0=0

3×1=3

3×2=6

3×3=9

....

3×50=150

6 0
3 years ago
The table shows the number of cups of water required when cooking different amounts of rice.
Harman [31]

<u>Answer-</u>

<em>The amount of water is the dependent value.</em>

<u>Solution-</u>

Plotting the graph from the given data points, it comes out to be a straight line with positive slope. So, both the variables i.e amount of rice and amount of water are in a linear relationship. They are directly proportional to each other.

As the amount of rice increases, the water needed to cook the rice also increases. Plotting a graph taking amount of rice in abscissa and amount of water in ordinate, a straight line was obtained.

Here, amount of rice is the independent variable and amount of water is dependent variable as it depends on the amount of rice.

3 0
3 years ago
Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero. Fill in the miss
mario62 [17]

Answer:

We conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

  • \frac{ad+cb}{bd}       ∵ b≠0, d≠0, so bd≠0

Step-by-step explanation:

Let a, b, c, and d are integers.

Let a/b and c/d are two rational numbers and b≠0, d≠0

Proving that the sum of two rational numbers is rational.

\frac{a}{b}+\frac{c}{d}

As the least common multiplier of b, d: bd

Adjusting fractions based on the LCM

\frac{a}{b}+\frac{c}{d}=\frac{ad}{bd}+\frac{cb}{db}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

          =\frac{ad+cb}{bd}

As b≠0, d≠0, so bd≠0

Therefore, we conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

  • \frac{ad+cb}{bd}       ∵ b≠0, d≠0, so bd≠0
3 0
3 years ago
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