All categories

3 years ago

What is the best approximation for the circumfrence of a circle with a diamiter of 400 inches

1 answer:

4 0

$\bf \textit{circumference of a circle}\\\\ C=\pi d~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=400 \end{cases}\implies C=400\pi \implies C\approx 1256.637$

You might be interested in

Please answer it soon

Jet001 [13]

Hey dude we’re both from Nepal so here’s the written worksheet hope it helps :)

6 0

3 years ago

What two numbers plus 35 equal 180

Andrews [41]

X^2+35=180?
Subtract 35 on each side

x^2=145
Take the square root

x= -sqrt(145)
+sqrt 145...

I hope this helps!!

4 0

3 years ago

Read 2 more answers

The students in Robbie's grade voted for a class field trip. 80% of the students

Aneli [31]

Answer:

I believe it's 192

Step-by-step explanation:

4 0

3 years ago

Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea

lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

$\int\limits^y_0 {kx^{2} } \, =1$

where y=23

Clearing k=0.00025

a) $Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5$

b) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2} =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6$

c) The function is equal to:

f(x)=k(1+2x)

$\int\limits^y_0 {k(1+2x)} \, =1$

where y=20

k=0.0024

$Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3$

d) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2} =198.4-176.89=21.51$

8 0

4 years ago

The U.S. Department of Housing and Urban Development publishes data on the fair market monthly rent for existing one-bedroom hou

Aleksandr [31]

Answer:

$n=(\frac{1.960(80)}{25})^2 =246.73 \approx 247$

So the answer for this case would be n=247 rounded up to the nearest integer

Step-by-step explanation:

We know that the standard deviation is :

$\sigma = 80$ represent the deviation

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =25 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution and the critical value would be $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(80)}{25})^2 =246.73 \approx 247$

So the answer for this case would be n=247 rounded up to the nearest integer

8 0

3 years ago

What is the best approximation for the circumfrence of a circle with a diamiter of 400 inches​

What is the best approximation for the circumfrence of a circle with a diamiter of 400 inches