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3 years ago

If it is 9:37 what time would it be a hour and a half later

Mathematics

2 answers:

adelina 88 [10]3 years ago

8 0

Answer:

it would be 11:07

Step-by-step explanation:

what grade are u in???

gizmo_the_mogwai [7]3 years ago

7 0

It would be 11:07 am/pm depends the question.

You might be interested in

I need help pls and explain

e-lub [12.9K]

Answer:

C. 29

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define Equation

1/4(d - 2) = 6

Step 2: Solve for d

Multiply 4 on both sides: d - 2 = 24
Add 2 to both sides: d = 26

Step 3: Find

Define condition: d + 3
Substitute in d: 26 + 3
Add: 29

5 0

3 years ago

Show work and explain with formulas.

vova2212 [387]

Answer:

$\large\boxed{4.\ S_{13}=260}$

$\large\boxed{5.\ \sum\limits_{k=1}^7(2k+5)=91}$

$\large\boxed{6.\ a_1=17,\ a_2=26,\ a_3=35}$

Step-by-step explanation:

We have:

$a_6=18,\ a_{13}=32$

These are the terms of the arithmetic sequence.

We know:

$a_n=a_1+(n-1)d$

Therefore

$a_6=a_1+(6-1)d\ \text{and}\ a_{13}=a_1+(13-1)d\\\\a_6=a_1+5d\ \text{and}\ a_{13}=a_1+12d\\\\a_{13}-a_6=(a_1+12d)-(a_1+5d)\\\\a_{13}-a_6=a_1+12d-a_1-5d\\\\a_{13}-a_6=7d$

Substitute a₆ = 18 and a₁₃ = 32:

$7d=32-18$

$7d=14$ divide both sides by 7

$d=2$

$a_6=a_1+5d$

$18=a_1+5(2)$

$18=a_1+10$ subtract 10 from both sides

$8=a_1\to a_1=8$

The formula of a sum of terms of an arithmetic sequence:

$S_n=\dfrac{a_1+n_1}{2}\cdot n$

Substitute a₁ = 8, a₁₃ = 32 and n = 13:

$S_{13}=\dfrac{8+32}{2}\cdot13=\dfrac{40}{2}\cdot13=20\cdot13=260$

===========================================

We have

$\sum\limits_{k=3}^7(2k+5)\to a_k=2k+5$

Calculate $a_{k+1}$

$a_{k+1}=2(k+1)+5=2k+2+5=2k+7$

Calculate the difference:

$a_{k+1}-a_k=(2k+7)-(2k+5)=2k+7-2k-5=2$

It's the arithmetic sequence with first term

$a_1=2(1)+5=2+5=7$

and common difference d = 2.

The formula of a sum of terms of an arithmetic sequence:

$S_n=\dfrac{2a_1+(n-1)d}{2}\cdot n$

Substitute n = 7, a₁ = 7 and d = 2:

$S_7=\dfrac{2(7)+(7-1)(2)}{2}\cdot7=\dfrac{14+(6)(2)}{2}\cdot7=\dfrac{14+12}{2}\cdot7=\dfrac{26}{2}\cdot7=(13)(7)\\\\S_7=91$

===========================================

We have:

$a_1=17,\ a_n=197,\ S_n=2247$

The formula for the n-th term of an arithmetic sequence:

$a_n=a_1+(n-1)d$

The formula of the sum of terms of an arithmetic sequence:

$S_n=\dfrac{2a_1+(n-1)d}{2}\cdot n$

Substitute:

$(1)\qquad 197=17+(n-1)d\\\\(2)\qquad2247=\dfrac{(2)(17)+(n-1)d}{2}\cdot n$

Convert the first equation:

$197=17+(n-1)d$ subtract 17 from both sides

$180=(n-1)d$ Substitute it to the second equation:

$2247=\dfrac{34+180}{2}\cdot n\\\\2247=\dfrac{214}{2}\cdot n$

$2247=107n$ divde both sides by 107

$21=n\to n=21$

Put the value of n to the equation (n - 1)d = 180:

$(21-1)d=180$

$20d=180$ divide both sides by 20

$d=9$

Therefore we have the explicit formula for the nth term of an arithmetic sequence:

$a_n=17+(n-1)(9)\\\\a_n=17+9n-9\\\\a_n=9n+8$

Put n = 1, n = 2 and n = 3:

$a_1=9(1)+8=9+8=17\qquad\text{CORRECT :)}\\\\a_2=9(2)+8=18+8=26\\\\a_3=9(3)+8=27+8=35$

4 0

3 years ago

There are 99 cats and 121 dogs participating in a costume competition. What percent of the participants are cats?

kakasveta [241]

About 81.82 rounded.

8 0

3 years ago

The age of an ancient tree trunk is estimated using radiocarbon dating. If the trunk has a C-14 decay rate that is 34% of what i

laiz [17]

Answer:

8923 years

Step-by-step explanation:

Half life of C-14 = 5730yrs

decay rate= 34%

Halt life (t^1/2) = (ln2) / k

5730 = (ln2) /k

k = (ln2) / 5730

k = 1.209 * 10^-4

For first order reaction in radioactivity,

ln(initial amount) = -kt

ln(34/100) = -(1.209*10^-4)t

-1.0788 = -(1.209*10^-4)t

t = -1.7088/ -1.209*10^-4

t = 8923 years

7 0

4 years ago

A window is twice as long as it is wide. The area of the window is 2x where x

Alchen [17]

Answer:

When we have a rectangle of length L and width W, the area is calculated as:

A = W*L

In this case, W = x, and the area is:

A = 2*x

Then we must have L = 2.

We know that the area of the window and the frame (together) is:

a = 2*x^2 + 12*x + 16

The area of the frame alone, will be equal to the difference between the area of both objects (a) and the area of the window alone (A)

area of the frame = a - A

= (2*x^2 + 12*x + 16) - (2*x) = (2*x^2 + 10*x + 16)

This is the area of the frame

5 0

3 years ago