Which of these could be the dimensions of a unit cube? Select all that apply.
2 answers:
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1. Method 1: By Listing MultiplesList out all multiples of each denominator, and find the first common one.
2: 2 , 4
4: 4
Therefore, the LCD is 4
Method 2: By Prime FactorsList all prime factors of each denominator, and find the union of these primes.
Therefore, the LCD is <span>2 x 2 = 4
</span>
2. <span>Make the denominators the same as the LCD
</span>
<span>
3. </span><span>Simplify. Denominators are now the same.
</span>
4. Join the denominators
5. <span>Simplify
</span>
<span>
Done! :) </span><span>Decimal Form: -0.25</span>
2: 2 , 4
4: 4
Therefore, the LCD is 4
Method 2: By Prime FactorsList all prime factors of each denominator, and find the union of these primes.
Therefore, the LCD is <span>2 x 2 = 4
</span>
2. <span>Make the denominators the same as the LCD
</span>
<span>
3. </span><span>Simplify. Denominators are now the same.
</span>
4. Join the denominators
5. <span>Simplify
</span>
<span>
Done! :) </span><span>Decimal Form: -0.25</span>
Answer:
Step-by-step explanation:
If x - 1 is a factor of the cubic, then 1 should result in 0 when you put it in the cubic for x. Does it?
f(1) = 2(1)^3 - 15(1)^2 + 22(1) + 15
f(1) = 2 - 15 + 22 + 15
f(1)= 24.
No the result is not zero. So x - 1 is not a factor.
However there must be something that makes this cubic go to zero. The easiest way to find it is to graph it.
The numbers that do make this zero are -0.5, 3, 5
Which mean that the factors are (2x+1)(x-3)(x - 5)
