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3 years ago

Consider the line through (-1, -4) and (1, 2). What is the slope (m) of the line?

Mathematics

1 answer:

zloy xaker [14]3 years ago

5 0

Answer:

3

Explanation:

$\bold{\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}}$

$\bold{\left(x_1,\:y_1\right)=\left(-1,\:-4\right),\:\left(x_2,\:y_2\right)=\left(1,\:2\right)}$

$\bold{m=\frac{2-\left(-4\right)}{1-\left(-1\right)}}$

Refine

m = 3

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Natali5045456 [20]

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2 years ago

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$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k$

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$\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx$

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$\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}$

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3 years ago

Consider the line through (-1, -4) and (1, 2). What is the slope (m) of the line?​

Consider the line through (-1, -4) and (1, 2). What is the slope (m) of the line?