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Luba_88 [7]
3 years ago
6

I need your assistance on this please!

Mathematics
1 answer:
Fantom [35]3 years ago
3 0
Substitute values and isolate v.

v^2 = u^2 + 2as
v^2 = 8^2 + 2(3)(19)
v^2 = 64 + 114
v^2 = 178
v = √178
v = about 13.3

Since the velocity isn’t exactly 13m/s, it cannot be A, so the correct answer is C.
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37 and 9/10
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In Bicycle Moto Cross (BMX) racing, racers purchase a one year membership to a track. They also pay a fee for each race at that
allsm [11]

Answer:

its 25

Step-by-step explanation:

if you divide 125 and 5 you get 25

then if you divide 170 and you get 21.25 but you want to round it to 25

hope this helps plz let me have brainliest

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3 years ago
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Someone pls help!! :/
Flauer [41]

Answer:

104

Step-by-step explanation:

ok so to find the area of this triangle you need to use the number you have witch are 16 and 13 so we wana find the area of one side of the triangle witch it has mark ware it needs to be split and so 16 / 2 is 8 and so we have 2 pairs of 8 and now you multiply hight by width and get 8 x 13 is 104 so we devide that by two in order to get one section of the triandle so 104 / 2 is 52 and thats one side of the triangle and now we add 52 by 52 and get 104

6 0
3 years ago
If 6 cards are drawn at random from a standard deck of 52 cards, what is the probability that exactly 2 of the cards are spades?
nataly862011 [7]

Answer:

<em>The probability of getting exactly 2 of the cards are spades out of 6 cards will be </em><em>0.315</em>

Step-by-step explanation:

6 cards are drawn at random from a standard deck of 52 cards.

The number ways 6 cards can be drawn from a deck of 52 cards will be,

=\ ^{52}\text{C}_6=20358520

In a deck of 52 cards, 13 cards are of spades. So drawing 2 spades out of 13 is,

=\ ^{13}\text{C}_2=78

As exactly 2 must be spades, so the remaining 4 cards must be drawn from other 39 cards of other suits. This can be done in,

=\ ^{39}\text{C}_4=82251

The probability of getting exactly 2 of the cards are spades out of 6 cards will be,

=\dfrac{\ ^{13}\text{C}_2\times ^{39}\text{C}_4}{\ ^{52}\text{C}_6}=\dfrac{78\times 82251}{20358520}=0.315

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3 years ago
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