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STatiana [176]
3 years ago
11

On a math test, the students are asked to

Mathematics
1 answer:
Luden [163]3 years ago
7 0

Answer:

Alberto is incorrect. Perimeter is 42 units.

Step-by-step explanation:

Given:

The vertices of the triangle are S(-6.5, -8.5), T(2.5, -8.5),U(2.5, 3.5), \textrm{ and } V(-6.5, 3.5).

Perimeter of a triangle of length l and width b is given as:

P=2(l+b)

Here, l=ST,b=TU

Distance between two points A(x_{1},y_{1}) and B(x_{1},y_{2}) is given as:

AB=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

So, the length ST is,

l=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\l=\sqrt{(2.5-(-6.5))^{2}+(-8.5-(-8.5))^{2}}\\l=\sqrt{9^{2}+0}=9

Width TU is,

b=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\b=\sqrt{(2.5-2.5))^{2}+(3.5-(-8.5))^{2}}\\b=\sqrt{0+12^{2}}=12

Therefore, the perimeter is given as:

Perimeter = 2(l+b)=2(9+12)=2(21)=42 units.

Hence, the perimeter written by Alberto is incorrect as perimeter is not 18 units bu 42 units.

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